The collision is perfect inelastic therefore after collision the bodies will move together.

The total linear momentum will remain conserved so assuminf theta be the angle between there bisector before the collision then cos of theta will be 0.5 therefore the value of theta will be 60 hence the angle

To get the solution of your query, I would suggest you to ask on https://www.entrance360.com/

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As the question is incomplete I can provide you with the concept when a body two body collides in a perfectly inelastic collision then the coefficient of restitution that is the ratio of velocity of separation to the velocity of approach becomes zero this the velocity of separation becomes zero

Hi

As the height is proportional to aware of the velocity therefore the height after the first bounce would be one fourth that is 5m.

Now the time for first bounce sq(20/10 *2) that is 2s.

Now time for second bounce 2 * sq (1) that is 2s.

Therefore total

Hello

If you are asking about CBSE syllabus of Class 11th, you can go through the link below to check-

http://cbseacademic.nic.in/curriculum.html#collapse11

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Delta l / L = 1000* g / 28*28* E 

Delta l = 12.51* L/ E 

Final length will be = delta l + L 

(12.51/E  + 1) *L

Hello Harshavardhan..we can't predict marks as it is percentile, but we can predict the rank.

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 3,98,273.

As per previous year

Hii

Yes ofcourse it is possible to prepare in 1 month if you are completely dedicated towards your studies and you focus on what you are studying.
You need not to leave the chance to appear in the exam. What can happen if you do not know a concept, some