Hello student ,

For artificial intelligence and hacking you can go for artificial intelligence specialization along  with b.tech and for hacking you can join any of the coaching institute as well. 

On the other hand you can for some online courses for both the courses you have mentioned above along

hello roshan

you can predict the colleges you can get by your rank in keam and 12 percentage using the careers 360 keam college predictor at https://engineering.careers360.com/keam-college-predictor. feel free to ask any doubts in the comments section.

hope it helps.

Hi, 

Here is the cutoff of Manipal:

Manipal Institute of Technology, Manipal

CSE:1893

ECE:4954

EEE:7433

Civil:16826

Biotech:24612

Sikkim Manipal Institute of Technology, Sikkim

CSE:41708

ECE:39356

EEE:38681

Manipal University, Jaipur

CSE:10867

ECE:24335

EEE:25593

Please visit the link below for detailed cutoff:

Https://engineering.careers360.com/articles/met-cutoff

Thank you.

Hi,
Here is the cutoff of Amrita Coimbatore.

Amrita School of Engineering, Coimbatore

Hello dear, 

According to your rank in VITEEE 2019 ,you have no chance to get seat in CSE in VIT vellore campus as the previous year closing rank for the same was under 10k.

Hello Jay!

Last year, the closing rank for CSE was, 1893. So, its quite evident that the posibility of you getting CSE in manipal is quite less.Same can be said for IT. There is slight chance for ECE. you can get rest all branches easily. Nevertheless, don't lose hope as

Hello Mridul,

JEE Mains is an annual exam that is conducted by the National Testing Agency and the CBSE for admissions to undergraduate engineering courses in NITs, IIITs, GFTIs and other institutes. It also serves as the first stage for admission to IITs through JEE Advanced.

EWS is a new

Hi Suman, congratulations for your admission in the college. In the first sem, you'll be mainly taught basic subjects like Physics, Maths and Chemistry. Along with these, one of the main subjects will be computer language: C. Of you've studied the same in school, it's really good but if not,

Hello Arun

With this percentile you can calculate your rank by using rank formula, You can calculate the predicted rank using the below formula but you cannot calculate the score using the percentile.

((100-percentile)*875000)/100

Your rank will be around 24k-25k. So, with this rank you can get NIT Rou or

Hii Manav

According to the previous year cutoffs the last rank getting admission in CSE IIT Hyderabad had secured a mark 256 in the Jee main while the Cutoff for NIT Trichy is as given below

The closing ranks for different categories are

Home state

GEN.                    4041

OBC NCL.           1407