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66 Views

hey is this important to have cs in 12th or not ,i want to do b.tech in cse

Nithesh 27th Oct, 2019

Hello !!Eligibility criteria to do btech in cse is just to pass your +12 with minimum pass percentage.Entrance examinations are available to get seat in good college,based on the scores also some colleges provide fee concessions.So..no need to worry just complete your +12 you can get into btech easily and

126 Views

cutoff for jee main to get NIT surat,CS branch

Sharon Rose Student Expert 5th Dec, 2019
Hello,
The seat allotment in JoSAA counselling 2019 were as follows for each category in 2019 for Sardar, Vallabhbhai National Institute of Technology, Surat. The cut off ranks are opening and closing rank respectively.
  • General category 1185 - 5262
  • EWS: 598-612
  • OBC-NCL: 1566-1811
  • SC: 768- 1013
  • ST: 377-426
  • General category
45 Views

How to become a nanotechnologist without CS??

rehan18alam Student Expert 26th Oct, 2019

Dear Aspirant,

Yes you can become a nanotechnologist without taking CS as your branch in engineering. After completion of your 12th in science stream with mathematics, you could apply for exam like JEE mains and advanced. After securing a good rank you can apply directly for B Tech in Nanotechnology.

208 Views

Ganpat University mehsana, average package and highest package for cs students

niharika cherry 4th Dec, 2019

Hi Vatsal!

Ganpat University, Mehsana packages depends on placements held in the college for every every year. They may change from year to year depending on company and depending on placements. The highest package offered is 12 lacs per year and average package is 3.09 lacs per year.

Hope this

127 Views

ma BTech karna chata hou cs ka saath IIT ma.kia muja JEE main and JEE advanced donohi karna paraga.

priyaankasarkar Student Expert 25th Oct, 2019

Yes. If you want to study in an IIT, you need to appear for both JEE Mains and JEE Advanced. JEE Advanced is the entrance examination for admission to IITs, NITs and GFTIs. To be eligible for JEE Advanced, you need to qualify in JEE Mains. For more information on

62 Views

I want to BTech in cs .what I do after 12th???

priyaankasarkar Student Expert 24th Oct, 2019

JEE Mains is the entrance examination for admission to most Engineering colleges across India including the IITs, NITs and GFTIs. For admission to IITs, NITs and GFTIs, you need to appear for JEE Advanced. Now, once you appear for JEE, based on your marks and rank in the merit list,

61 Views

how much number get in JEE main exam ?? because I want BTech in cs

ANPAM KUMAR Student Expert 24th Oct, 2019

Hey there

Different colleges have different Cutoffs and for cs also different colleges have different opening and closing ranks. As you have not mentioned any college so for nits if you want cs not in top nits then 175+ is a decent score for that.

Check Cutoff for jee jee

104 Views

I got passed in 12th with PCMB subjects nd then take admission in bsc cs(computer science) now i am in second year nd want to give neet ug exam.. am I eligible????

priyaankasarkar Student Expert 24th Oct, 2019

Yes you are eligible for NEET. Now there is no upper age limit for NEET. If you have completed your 10+2 with Physics, Chemistry and Biology with a minimum aggregate of 50%, you are eligible for NEET. It is 50% for General Category, 45% for PWD and 40% for OBC,SC,ST.

69 Views

How to apply for bsc cs in Christ university banglore?

Nakkina Sai Bhaskar Student Expert 3rd Dec, 2019

Hii,

Christ University Bangalore offers Bachelor of Science Course in various Specialisations like physics, Electronics, Chemistry, Bio Technology, Botany, Mathematics, Zoology, Computer Science  and Statistics. BSc is a 3 year full time degree. The fee structure of the Course is 65,000.

76 Views

if i get 8000 obc rank, can i get cs in nit allahbaad?

Devraj Student Expert 25th Oct, 2019

Hii

Of course NO. If you don't have HS category than you may not get any of branch for admission in MNNIT allahabad.

In case you want admission in CSE at MNNIT-A then you need rank under

For HS-1468

OS-1154

hope you understood it. All the best for exam .

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