Hello!!!!!!

Hope you are doing great!!!

Your All India rank would be 48664 approximately using the formula 100+94.4*869010/100 where 94.4 is your percentile and 869010 is the number of candidates who appeared for january session.As per the previous year scenario ,you can get in mechanical branch in NIT Hamirpur under home state quota.You cannot get seat in NIT Jalandhar  in computer science and mechanical branches with this rank.For checking the probabilities of colleges or NIT's , you can use our college predictor.The link is the provided below:

https://engineering.careers360.com/jee-main-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-College-Predictor Hope it helps!!!!

Good luck!!!!!

Hi Piyush,

Here, you have ot mentioned your category, your home state and gender.

So, I am giving the cutoff ranks of 2019 for General category, home state and male gender to take admission in NIT Jalandhar, so you can get an idea of this year's cutoff:-

• Bio Technology - AIR 79784
• Chemical Engineering - AIR 53704
• Civil Engineering - AIR 48106
• Computer Science and Engineering - AIR 10800
• Electrical Engineering - AIR 27654
• Electronics and Communication Engineering - AIR 18724
• Mechanical Engineering - AIR 35515
• Textile Technology - AIR 91133
• Information Technology - AIR 13479
• Instrumentation and Control Engineering - AIR 41988
• Industrial and Production Engineering - AIR 83356

Refer here for more info - https://engineering.careers360.com/articles/jee-main-cutoff-nit-jalandhar

Feel free to ask doubts in the Comment Section.

I hope this information helps you.

Good Luck!

without GATE a non-IITian or NIT-ian cannot get M.Tech in any of the government colleges.

Hello,

Your expected will be around 182492.You can calculate your expected rank using the formula (100-your total percentile)*869010/100

where 869010 is the total number of candidates appeared in January session,In april session 1200000 candidates are expected to appear then your expected rank can be calculated using the formula (100-your total percentile)*1200000/100

Now, your category rank will be around 8k-9k.In 2019 a candidate belonging to SC category with rank 5763 secured a seat in ECE in NIT, Jalandhar.So you may have less chaces to get seat in this college.However, cut off is subjected to change it may increase or decrease slightly.

You  can predict the colleges in which you may get seat  by using the link below

https://engineering.careers360.com/jee-main-college-predictor

92.5 is a very good score, so before answering your question I would like to Congratulate you and with this rank, you will definitely get admission to a good Institution. Your rank can be predicted between 55k-65k as compared to last year ranks in this percentile.

The formula to calculate the NTA score is:

Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) EQUAL TO OR LESS than the candidate) / (Total number of candidates who appeared in that session).

But as compared to last year closing ranks for the CSE/IT branch is approx 11k and 14k for home state category, so its difficult for you to get admission in NIT Jalanadhar. I suggest you to look forward to other colleges.

Best of luck!!