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73 Views

will any iit take the rank in JEE main paper 2 exam without JEE main and advanced result??

Subhodeep Biswas 26th Jan, 2020
Hey there hope you're doing well.
Dear aspirant, no any IIT is not going to take the result of JEE MAIN examination paper 2. It is organised only for admission for B.arch. programmes at nits and other colleges over India.
Also if you have a dream to study arch .
54 Views

With 85.06 percentile in JEEE B planing 2020 , which all collages I can get admission

Suryashis Chakraborty 26th Jan, 2020

Hello Aniruddha,

Congratulations on your performance!

According to our Rank Predictor your estimated rank is roughly around 16,834. It is really difficult to get anything substantial with such a percentile.

You should look for private colleges like SRM University and Amity University.

You can also look upto our college predictor

59 Views

I want prediction for Paper 2 score. My percentile is 98.89 in JEE Main of Jan 2020

Nihal Kumar Gupta Student Expert 25th Jan, 2020

Hi  Binayak,

You got 98.89 percentile in JEE main exam, your rank would be approximately in between 1000 to 2000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your

212 Views

My percentile is 93.8 in b arch.What are my chance of admission in NIITs or some other places.

SAKSHI KULSHRESHTHA 25th Jan, 2020

Rajesh, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:

(100-your total percentile) x 112679/100

So with 93.8 percentile, your rank would be around 6986.

Most top colleges in India require a rank of 5000 or below in JEE Mains paper

53 Views

my percentile for mains paper 2 is 68.023 what is my rank

Pachigolla Hemanth 24th Jan, 2020

Hello Mulange vishnu prasad,

you can predicate your rank by using the formula.,

(100-your percentile)*no.of students wrote the exam/100,for the january exam total no of students are 112679,by this you can find your rank.

Then you rank is to be 36301

And also rank will be changed after the April

64 Views

I have got 84percentile in b.arch and 87percentile in b.planning and i am obc general category , am i eligible to do b.arch course in NITs

jishua thomas 26th Jan, 2020

hello aspirant....

as per the result analysis of last year, you need to have a percentile of 95 plus for the obc category to get admission in any nits for planning or architecture. though there will be a slight relaxation in the cutoff of this year due the increment in

47 Views

sir,i got 87.9percentile in b.arc.,i m general category female from telangana.can i got admission?

Sudarshan kumar 24th Jan, 2020

Hi Sreeja,

Your percentile is not good enough to get into any NITs or IIITs even in female quota. You should prepare more harder to get better percentile then this to get into NITs or IIITs or any other good government college.

You should also Check cutoff by yourself at

33 Views

how can i convert my nta score of paper 2 2020 into percentile

Harshita Gupta 24th Jan, 2020
Hey, the score that you see in your result is actually percentile. Once you have your percentile, you can predict your rank using the formula:

(100 - your total percentile score) X 112679 /100 .

(100-your total percentile score) is the percentage of people ahead of you.
112679 are the
57 Views

My note score 93.74 in B.arch in obc ncl.Can I take admission.

Nihal Kumar Gupta Student Expert 24th Jan, 2020

Hi Jai,

You got 93.74 percentile in JEE main 2 exam, your rank would be approximately in between 7000 to 8000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check

74 Views

what are the B.Arch colleges i can get into with 98.15 percentile score in paper 2 . can you send the last year ranks for referece

LAKSHMI AMBIKA 23rd Jan, 2020

Hello Manoj,

First of all congrats for your good marks. for your percentile you can predict your rank by using the formula (100-your total percentile)*112679/100 . and here 112679 is the number of candidates appeared for the jan exam and it changes after the april exam as the number of

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