Jaypee Institute of Information Technology, Noida
Hi,
The cut-off rank for ece branch in the round 10 last year was 96486. Since you have 90 marks your rank would probably be somewhere between 70000-100000. So, I think you have a very good chance.
Furthermore, if you want you can check your other options with the JEE College predictor:
https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp
The admission in Jaypee Institute of Information Technology can be taken from one of the following modes:
1. Based on JEE Marks
2. Based on Class XII percentage.
The cutoff are subject to change depending on the difficulty of the paper etc. The last year's closing rank for JEE mode were:
Round 1: 32373
Round 2: 36510
Round 10: 444765
Final Round: 46322
The Cutoff for merit-based entrance was: 96.33%
For More information refer to: https://www.jiit.ac.in/faq
Hello Ujjawal
JIIT Noida, JUIT Solan, JUET Guna, and JU Anoopshahar are the four institutes owned by Jaypee. One application must be submitted for all Jaypee campuses in order to be admitted. It would, however, be an admission based on JEE Mains. You must fill out a new form for direct admission just using your 10+2 marks, which is only available at JUET Guna and JU Annopshahar.
Thanks
Hey aspirant
Admission to jiit noida is by both entrance and merit. You can get admission based on your merit in 12 according to the seat available. You need to fill application form and attest your mark list along with it. Marks of physics and maths are compulsory. You can add any other subject according to your choice.
Chances for getting cse for 90% is low . Last year cut off was 92%. But you will get admission for other branches like IT, biotechnology etc
Hey Students,
JIIT Noida provides multiple courses. You're definitely not clear with your question as you haven't specifically mentioned the course you are asking about. Every course has it's own admission procedure.
Yes, with 91.60% in your 12th you're definitely eligible for getting admission in Jaypee University (JIIT), Noida. The basic minimum eligibility criteria required 50% in 12th.
For further information visit the link given below:-
https://www.careers360.com/university/jaypee-institute-of-information-technology-noida/admission
KIET Ghaziabad:
JIIT Noida:
Now, It's your choice which you want to your further studies to enhances your skills.
Hello Aspirant,
For B.Tech Cse in JIIT Noida,
Physics and Mathematics are mandatory subjects; at least 80% score or coequal grade.
So you are eligible.
Jaypee Institute of Information Technology, Noida was inaugurated in 2003 is an academic university fully supported and funded by Jaypee Group of Companies. JIIT presently gives B.Tech, M.Tech, MBA and PhD degrees.
The university has 6 deptt.
Biotechnology, Computer science & IT, Electronics & Communication, Mathematics, Physics & Material Science and Humanities & Social Science. All the programs given by the university are full-time.
The university possesses 5 campuses I.e.,
Jaypee University, Anoopsar
Jaypee Institute of Technology, Noida
Jaypee Business School, Noida
Jaypee University of Information Technology, Solan
Jaypee University of Engineering & Technology, Guna (M.P)
Candidates qualified for Higher Secondary exams can opt for the UG courses.
Learners who aspire to pursue admission to JIIT can go for both offline and online modes.
The entries to B.Tech are founded on the merit list by JIIT and entries for the other courses are established on the entrance test and personal interview.
Nomination method for B.Tech
Reliable achievement in JEE (Mains) and 12th score.
Regards.
JAYPEE INSTITUTE OF INFORMATION TECHNOLOGY is a Deemed to be University which is a Private University. It offers the courses stated below:
The admission to the course of BTech are provided on the basis of JEE Main .
For more information regarding the preparation tips for JEE MAINS consider the link below:
https://engineering.careers360.com/articles/how-prepare-for-jee-main
I hope this helps. Wish you a great day!
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