JEE Main Paper 2
hello aspirant..
you can try for the school of planning, delhi, spa vijayawada and spa bhopal . nit trichy or nit calicut is also a good option for you..
If you have qualified the jee mains paper 1 you can try for the iit s for architecture, such as the
for admission in nit you need to have a minimum of 99 plus percentile for the jee mains paper 2 examination for the general category. there will be sight relaxation in the cutoff due to increment in the seats of some nits for architecture but this wont be
Hello!
At 96 percentile, the rank shall be around 8000. The closing rank for B.Arch of 2019 of National Institute of Technology, Tiruchirappalli ( NIT Trichy ) was 1075 for General category in Other State quota. In the year 2018 the closing rank was 670.
So, there is no chance
You can easily get admission in Veer Surendra Sai University of Technology (VSSUT) as your rank will be around 35,000.
At this percentile you have little chance to get admission in NITs. You can go through this link for the opening and closing ranks of different colleges. ( https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning )
Hello,
Your son really got good percentile. You haven't mentioned category and home state. This year total 112679 students attempted jee paper2. You can calculate his approximate rank using :(100-percentile)*112679/100. That is 2,242. Yes he will get an NIT for sure. You can see last year cut off of Rourkela
Hey Sreekripa,
According to the formula (100 - your total score) X 112679 /100 your estimated rank is coming out to be AIR 5070 which is a decent rank for JEE- Main paper 2. Your overall rank can vary as the number of students appearing in the April attempt may
HELLO SUSHMA It is very difficult to Predict the actual rank since it depends on various factors> your expected rank comes out foer the jannuarys ession coems out to be around 16901. the expected rank might change depending on the no of candates appearing the april session. since the officials
Hi Ranjeet,
You got 94.38 percentile in JEE main 2 exam, your rank would be approximately in between 6000 to 7000. Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check
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