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JEE Main Paper 2

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907 Views

My son got 91.57 percentile in B.Arch jee main paper 2. Can he get good NIt.

Sudarshan kumar 23rd Jan, 2020

Hi sir,

In this rank your sons rank would be around 9k-10k.

And in this he won't get any good NIT college.If you belong from OBC then there will be some chances of getting NIT Patna or some lower rank NIT.

I would suggest him to work hard and get

1356 Views

how to calculate the rank from percentile score for JEE MAIN PAPER 2 ?

Yashu Shrivastava 23rd Jan, 2020

Hello Devinandana

To calculate your rank from percentile of JEE MAIN PAPER 2

100-your total percentile score is the percentage of people ahead of you.112679 are the number of candidates appeared for January exam.

So rank formula will be (100-your total score)*112679/100

I Hope This Information Will Help

Best Wishes

85 Views

i got 81 percentile in jee paper 2. Which college i can get? And what will be the minimum score i have to get in Cbse to boost my score and what will be my rank?

Rishi Garg 26th Jan, 2020

You can calculate your rank in JEE Main Paper 2 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 (Jan) are around 112679, your rank will be around 21500. However as the no. of students in April changes,

65 Views

My percentile in b. Arch is 52 and b. Planing is 59.9 and i am from st group is there any nit available m also from arunachal pradesh

Nihal Kumar Gupta Student Expert 28th Jan, 2020

Hi  Ongseng,

You got 59.9 percentile in JEE main 2 exam, your rank would be approximately in between 45000 to 50000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check

119 Views

Is there any chance to get into nit for 94.06 perctile 2020 in obc catagory jee main paper 2

Pooja Kaushik 23rd Jan, 2020
Hi Ashira,
you have got a really very good percentile and your chances are really high to get admission.
Hope for the best.
Good luck.
114 Views

i got 94.18 nta score in jee mains paper 2. which college will i get?

LAKSHMI AMBIKA 23rd Jan, 2020

Hello Dipesh Mahato,

For your nta score you can predict your rank by using the formula:

(100-your total score)*112679/100.

and you can use careers360 college predictor to get to know your colleges:

https://engineering.careers360.com/jee-main-architecture-college-predictor

and you can also use the below link for further reference:

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

Hope the answer is helpful.

110 Views

what is my rank if my percentile is 82.599 in b.arch????

Ayush Mishra 23rd Jan, 2020

Hey aspirant!


National Testing Agency (NTA) has declared the results of JEE Main 2020 Paper 2.


Now, to calculate your rank for B.Arch based on the percentile score that you have secured, you can use this formula:


(100 - your total percentile score) is the percentage  of people ahead of

1806 Views

What is minimum percentile required in jee main paper 2 to get seat in top NITs for barch.

S. Saha Student Expert 23rd Jan, 2020
Jee Main paper 2 cutoff varies from one institute to another. But on an average, to get into top NITs under AIQ such as NIT Trichy, Calicut, Rourkela, Jaipur, Nagpur etc. you need to secure a rank within 1000, for which you need to score at least 99 percentile in
69 Views

I written the jee 2020 exam but the result shows nothing and it is in the form of ---,can you please tell me what i have to do

Sujatha Venkat 23rd Jan, 2020

Hello perimala,

Don't worry it may be due to the server problem you were not able to look the results. Now there are websites working properly. Kindly visit jee main page again and check your answers. Keep up your spirit and wish you luck.

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