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JEE Main Paper 2

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I scored 97.4 percentile in jee main paper 2 will I get a better NIT

ARNAV SATRUSAL 29th Jan, 2020

Hi Byram,

Congrats on scoring 97.4 percentile and I would like to inform you that your rank will be something around ((100-97.4)*112679)/100 i.e something around 3k. Yes there is possibility of getting a seat in NIT. Also, as the number of candidates appearing the exam will change in April, your

295 Views

sir i got 71.8% in jee main paper 2 what would be my total score in marks

Mihir Varshney 24th Jan, 2020

This will help you in answering for paper 2.

National Testing Agency (NTA) has released JEE Main 2020 Paper 2 result.

To calculate the rank for B.Arch:

100 - your total percentile score is the percentage  of people ahead of you. 112679 are the number of candidates appeared for January

130 Views

how to calculate score by percentile

Vikas gehlot 24th Jan, 2020

You cannot calculate score from percentile.

the percentile days you're the relative position among the candidates who appeared for the exam.

Percentile indicates the percentage of students are behind you out of all those who appeared for the exam.

If you have your choices marked in the exam and interested

224 Views

I have got 68.17 percentile in jee main paper 2 and have reservation(st) can I get seat in nit??

jishua thomas 24th Jan, 2020

hello aspirant,.

nta have not released the jee mains paper  2 cutoff for this year. so you cannot actually predict the cutoff for this year, also there will be slight relaxation in the cutoff as the seats for the architecture and planning in certain nits have been increased. so you

65 Views

i got 75.82 percentile in jee main paper 2 and i am general. what coleges can i get?

SAKSHI KULSHRESHTHA 24th Jan, 2020

Tuhin, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:

(100-your total percentile) x 112679/100

So with 75.82 percentile, your rank would be around 27245.

According to your rank, it will be difficult to get a seat in the top colleges.

257 Views

I got 75.28 percentile in jee main paper 2 . what colleges can i get?

Pachigolla Hemanth 23rd Jan, 2020

Hello Tuhin Jyoti Kashyap,

According to the previous data,if you get 75.28 percentile in the JEE mains paper 2,then you have very less change to get seat in the colleges.So it is better to write the exam again in the month of April . And also make a plan for

74 Views

what are the B.Arch colleges i can get into with 98.15 percentile score in paper 2 . can you send the last year ranks for referece

LAKSHMI AMBIKA 23rd Jan, 2020

Hello Manoj,

First of all congrats for your good marks. for your percentile you can predict your rank by using the formula (100-your total percentile)*112679/100 . and here 112679 is the number of candidates appeared for the jan exam and it changes after the april exam as the number of

528 Views

i got 71.18 percentile in jee main paper 2 barch. can i get a seat in nit?

Akshat 19th Sep, 2020
Hi!
Congratulations for clearing your Board Examination and JEE Main.

You can check the opening and closing ranks of Architecture Colleges for year 2019. This will give you an idea about the ranks and  counselling.

Check this article published by Careers360. This will help you.

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

Good luck
907 Views

My son got 91.57 percentile in B.Arch jee main paper 2. Can he get good NIt.

Sudarshan kumar 23rd Jan, 2020

Hi sir,

In this rank your sons rank would be around 9k-10k.

And in this he won't get any good NIT college.If you belong from OBC then there will be some chances of getting NIT Patna or some lower rank NIT.

I would suggest him to work hard and get

1356 Views

how to calculate the rank from percentile score for JEE MAIN PAPER 2 ?

Yashu Shrivastava 23rd Jan, 2020

Hello Devinandana

To calculate your rank from percentile of JEE MAIN PAPER 2

100-your total percentile score is the percentage of people ahead of you.112679 are the number of candidates appeared for January exam.

So rank formula will be (100-your total score)*112679/100

I Hope This Information Will Help

Best Wishes

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