Correct Answer: Rs. 12,036

Solution : Let the cost price of the T.V. as C.
From the problem,
If the T.V. had been sold for Rs. 714 more, the gain would have been 15%.
⇒ 1.08C + 714 = 1.15C
⇒ 0.07C = 714
⇒ C = Rs. 10,200
The selling price for an 18% gain = 1.18C = 1.18 × 10200 = Rs. 12,036
Hence, the correct answer is Rs. 12,036.

Candidate should have completed 10+2 or an equivalent examination to apply for admission to BE/B.Tech programme at KCT Coimbatore.

Following specialisations are offered for BE/B.Tech courses—Aeronautical Engineering, Automobile Engineering, Biotechnology, Civil Engineering, Computer Science and Engineering, Electrical and Electronics Engineering, Electronics and Communication Engineering, Electronics and Instrumentation Engineering, Fashion technology, Mechatronics techology, textile technology, artigical intelligence and data science.

Kumaraguru College of Technology (KCT), Coimbatore is a private Engineering College started in 1984 under the auspices of Ramanandha Adigalar Foundation, a charitable educational trust of Sakthi Group.

Situated in a sprawling 156-acre campus in the IT corridor of Coimbatore, KCT is an autonomous institution affiliated to the Anna University, Chennai and approved by All India Council for Technical Education (AICTE).

KCT Coimbatore is a private engineering college situated in an extensive 156-acre campus. Kumaraguru College of Technology courses list includes 15 UG programmes, 16 PG programmes and 6 doctoral courses. 11 academic departments of the institute are recognised as research centres that permit research leading to Ph.D. degree given by Anna University. All the KCT UG programmes are accredited by NBA. KCT Coimbatore courses are offered in full-time mode only. You can apply for all KCT courses online as well as offline. KCT Coimbatore fees vary from course to course.

Hi,

I hope you are concerned to Kumaraguru College of Technology (KCT) . It was started in 1984. It is located in Coimbatore, Tamil Nadu. It offers various engineering fields like CSE, Electrical, Mechanical etc. It is a private college.

You need to go through TNEA counselling process, to get admission in the college.

Since, you haven't mentioned your general rank, it is difficult to analyze the records.

I suggest you to use T NEA College predictor offered by Careers360, it will help you to predict your personalized colleges based on your rank . https://engineering.careers360.com/tnea-college-predictor

I hope it covers your query.

Thank you!