Hello Aspirant,

Yes, you can get LNMIIT  Jaipur with 96.8 percentile in JEE Mains. You can get admission in several branches like Communication and Computer Engineering (CCE) and Electronics and Communication Engineering (ECE).

If you want to know more about the colleges you can get with this percentile.Please visit the link given below -

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Hello aspirant, Nirma University has started online application for B. Tech courses from 15 April and the last date to fill form has been extended till 30 June. LNMIIT Jaipur has also started online application for admission on JEE mains basis from 5 may and the last date to apply is 30 June.

Currently you have to fill JEE mains percentile in Feb, and march attempt for both universities and a merit list will be prepared on that basis and accordingly admissions will be done. So currently they have not provided any confirmed information about the other JEE attempts which have not happened so there is a probability that for now the merit list will be made only on basis of Feb and march attempts. Further they may ask for other two percentile once the exams have been held but now there is no clarification on that matter. In case of identical percentile, the tie-breaker criteria used will be

• Mathematics NTA Score (Percentile) in JEE (Main) 2021

• Physics NTA Score (Percentile) in JEE (Main) 2021

• Chemistry NTA Score (Percentile) in JEE (Main) 2021

• Total Percentage of marks in Class 10th examination

BEST OF LUCK!!

Yes, you can get LNMIIT Jaipur with 96.25 percentile in JEE Mains. You can get admission with this percentile into several branches like Communication and Computer Engineering (CCE) and Electronics and Communication Engineering (ECE). In case if you are seeking to get admission to Computer Science and Engineering (CSE) branch at LNMIIT Jaipur then it would not be possible with a 96.25 percentile. If you want to get admission to an even more good branch at LNMIIT Jaipur then you should attempt JEE Mains once again next year to improve your percentile.

You can also predict your college at JEE Mains 2021 College Predictor at Careers360 from the following link:

https://engineering.careers360.com/jee-main-college-predictor

Dear aspirant,

There is as such no minimum percentile pre decided as the cut off changes according to the factors such as the number of candidates applying for the college and also upon the seat vacancy. But if I had to go with previous years then the minimum percentile to get computer science and information technology is 96.5 approximately.

Coming to the second part of the question, for jiit noida as per the general category in cs and it branch, minimum 95+ will be a safer side.

For more information you can check out the link given below-

https://www.careers360.com/university/jaypee-institute-of-information-technology-noida

For more information you can check out the link given below-

https://www.careers360.com/university/lnm-institute-of-information-technology-jaipur

hi..

To be eligible in First Semester, candidates should have JEE (Advanced) AIR rank up to 12000 OR JEE (Main) Percentile of 97 and above. To be eligible from Second Semester onwards, candidates need to maintain a CGPA of 8.50 or above and no backlog.

With 95.4 Percentile in JEE Mains 2021, I would suggest you to prefer CCE at LNMIIT Jaipur over UIET Chanidgarh ECE. LNMIIT Jaipur is an excellent technical institute having strong faculty, infrastructure and placements with Top Recruiters like IBM, Infosys, Microsoft, Amazon, TCS, Wipro, Accenture, InfoEdge visiting campus each year. The Institute provides effective technical education besides having a strong employer outlook.

For more information about LNMIIT Jaipur do follow the link below

https://www.careers360.com/university/lnm-institute-of-information-technology-jaipur/amp

For more information and college prediction do follow the link below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Dear aspirant,

As you have mentioned that lnmiit jaipur has released their application form and as we all know due to the pandemic the boards including the 12th is cancelled so there is no point of the eligibility criteria which is " Candidates must have passed 10+2 equivalent examination with a percentage of atleast 60%  from any recognised board or university."

So, you will be admitted mainly on the basis of your jee scores. As your 2 jee attempts are still left so you need not worry they would inform you about the which score would be considered.

So, you can fill the form now irrespective of your 12th exam. A merit list would be prepared on the basis of jee scores.

For more information you can check out the link given below-

https://engineering.careers360.com/articles/lnmiit-btech-admission

hi...

LNMIT and VIT are good for CSE group but LNMIT is a government college and VIT is a private college. LNMIT placement is good.

Hi,

As of now, there is no latest announcement from LMNIIT regarding lateral entry admissions. However, here is a list of courses and number of seats that were offered for the year 2020:

For lateral entry in LNMNIIT, you must have scored atleast 75% or equivalent CGPA in 1st and 2nd semester of B.Tech/BE without any backlogs. Also, the candidate must have appeared in JEE, also one must have secured an aggregate of at least 60% Marks or Equivalent Grade in Physics, Chemistry, and Mathematics in Class 12th Examination.

For more details and updates, you can refer to this link: https://admissions.lnmiit.ac.in/ugadmissions/Lateral-Entry-Mode.html

I hope this helped you.

Hello Mehul,

Yes you are eligible for the admission in LNMIIT in CSE as according to your marks, your percentile will be above 99.23 and you need 97 percentile or above to get admission here.

Or you can get admission through JEE advance if you secure a rank below 12000.

You can also check more colleges according to your percentile through our rank predictors -

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

I hope it helps,

Best of luck