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2309 Views

If n^ is a unit vector in the direction of vector A then vector n is equal to?

Vikas gehlot 19th Nov, 2018

To find the unit vector of any vector you need to divide the vector by the magnitude of the given vector itself to find the unit vector in the direction of the goven vector.

You are given a vector A then you need to divide it by the magnitude of

96 Views

Any body can solve my doubt in physics, chemistry,Mathematics in this subject please give me his/her whats app number. Please please ple..

Vikas gehlot 18th Nov, 2018

There are many websites out there where you can post your doubt and get the solution.

You can search out for those platform online and post your dound there, some of them are free and some are paid so you can just try them out and find the best among

284 Views

The general solution of y-y+y^2cosx=0?

Ruchika Chauhan Expert 28th Dec, 2018

Hello Kashish

You can ask your subject related queries on the Entrance360 platform, using the link below- https://www.entrance360.com/all-questions/

Good Luck!

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83 Views

A committee of 5 is to be choosen from a group of 9 people. The probability that a certain couple wil either serve together or not at all is

Vikas gehlot 17th Nov, 2018

The Total Number of all the possible ways of Selection is 9C5=126

Now if there is a certain couple which is To be Placed Together, then You can consider them One so that they will be placed Together,

Now there arise two cases.

If a couple is selected, then we

463 Views

There are only two womens among 20 person taking part in a pleasure trip. The 20 persons are divided into two groups, each group consisting

Vikas gehlot 17th Nov, 2018

Total Number of Way of Dividing into Two Groups 20C10=184756 ( Which is same is selecting 10 People from 20)

Since the two women are to be together in the same Group, consider then One

Now two cases arise we will talk of only selecting one group and the other

269 Views

Sir cengage is books is good for maths or Bansal classes material is good for maths. Service is good

manisha.gupta 16th Nov, 2018

Firstly I would suggest you to go through well with NCERT books as it will help you to clear your basic concept then you can prefer the other books.

Cengage is also preferable book by the student for self preparation & Bansal is also renowned institute for JEE Preparation if

99 Views

Sir I can complete the cengage so sir I can complete the Bansal classes material of maths . Complete or not

harsh Student Expert 2nd Dec, 2018
Bansal classes study material is far better because it is the well settled and well planned material.
Cengaga have number of questions repeated number of times.
And the quality of Bansal study material is very good.
Instead of the quantity in cengaga.
So I would suggest you to go through
73 Views

Hi, can you tell me for a decent MBA college is it necessary to have good score in mathematics in 10-12? They check that ?

bilwma.basumatary 16th Nov, 2018

Hello, some of the top mba colleges in India are 1. Indian Institute of Management, Ahmedabad 2. Indian Institute of Management, Calcutta 3.  Indian Institute of Management, bangalore 4. Indian Institute of Technology, Kharagpur 5. Xavier School of Management, Jamshedpur 6. Shailesh J Mehta School of Management, Mumbai 7. Indian

59 Views

When will the application form for getting admission for doing mathematics honours in st. Xaviers college, Kolkata come out for new year??

Debosmitha Bhattacharyya Student Expert 15th Nov, 2018

Hello,

As on the official site the last date for online application (revised):  11 June 2018, 12 noon for B.M.S. course and 12 June 2018, 12 noon for all other courses.

So we can assume that you should start keeping an eye on the official site just after the release

1827 Views

I got 5.3 CGPA out of 10 in M.Sc. Mathematics. Am I eligible for CSIR-NET exam?

Kumud Sahni 15th Nov, 2018

Hello Rayala,

The eligibility criteria for UGC Net says 55% marks for general category while 50% for SC/ST category applicants. You must convert your cgpa to the percentage and check whether you are eligible for it or not. For any other details, you can check the link below.

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