Narula Institute of Technology, Agarpara
Hello gaddam!
jee advanced minimum percentile qualification is 70 percentile as declared by the NTA.
The nit admission minimum qualification percentage in class 12 is
General category - 75%
Sc/st category - 65%
Or the top 20 percentile in the class 12 exam conducted by your respective boards.
Hello Sagar. You have a decent score. It means that almost 16.67% of the total no. of students who appeared in the exam are ahead of you. (Tot. students- 874469)
It is difficult to tell if you will be getting nit college now since your percentile and rank may differ
hii sah
frankly to say you have very low percentile , while its hard to decide by the percentile as the admission goes by RANK not by percentile since find out your RANK fallow the below way
To calculate you rank you can use the formulae given below -
Rank=(total
Hello Navyasri..
Percentile= (marks you got*100)/(toppers marks in that session).
According to careers360 rank formula,
Rank formula= [(100-total score) * (no of students wrote exam)] /100
No of students attended are 874469.
So your expected rank will be nearly around 1,05,933.
As per previous year jee mains, any rank below
Hello Kanhaiya kumar..
So your expected rank will be nearly around 2,49,661.
As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.
Hello Harshavardhan..we can't predict marks as it is percentile, but we can predict the rank.
So your expected rank will be nearly around 3,98,273.
As per previous year
It depends on how many students are secured percentile between your percentile and 100 percentile and also on April jee so wait
Hello
Greetings
Your percentile is 93.734 It means 93.734% student of the Total student appeared for the Exam are Behind You Therefore 6.266% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 54794.2
Your Rank would change Either Your Percentile Score
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