hello aspirant,

As of now its tough to estimate what is the exact mark you need to get more than 99 percetile but based on previous year analysis we will help you.each year the cutoff changes due to many factors like total students appearing for exam,difficutly level etc factors so

Hello Aspirant,

If we go through the analysis of marks Vs Percentile Vs rank for JEE-Main 2020 then according to the marks mentioned by you in the question your rank and percentile is expected to be in the range of 34966 - 27838 and 92-95 respectively, you can check out

Perhaps, what you saw for NIT Durgapur on Careers360 Website is the OBC Category Rank and not CRL, hence the Confusion. While that mentioned under General is the CRL Rank. Both are different, as are the SC and ST Ranks under different Categories.

For more information and NIT Durgapur Cutoff

Hello,

Considering the previous year cut off and the expected rank that you have specified  you have chances of getting seat in

• Dr. B.R Ambedkar National Institute of Technology, Jalandhar: Bio-Technology, CIVIL Engineering, CSE
• Malviya National Institute of Technology, Jaipur: Mechanical Engineering
• NIT, Calicut: Civil Engineering
• NIT, Goa: ECE
• NIT,

Hello candidate,

The exact cutoff for the exact marks cannot be decided for this year's JEE main examination, based on previous years trends, one can predict the estimate of the expected opening and closing rank.

The cut off rank for Computer Science Engineering in OBC category was 13717 for other

Himanshu,

As per previous years records, you need to score atleast 160+ score to get 99+ percentile with your OBC category. With these marks you will be able to secure a rank of below 6,500. And if you are able to secure more than 200 marks then you might secure

Hello,

It is difficult to predict the exact marks as the cut off changes every year depending on number of candidates qualified, difficulty of exam and number of seats available etc.

To check the cut off for NITs click the link below

https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

Considering the past years cut off trends

Hi

This is a bit difficult to predict the marks/percentile/rank required in JEE mains to get a seat in nit/iiit as cut off  keeps changing every year  depending upon various factors like  number of students that appeared in the exam, kind of marks obtained by them , toughness level of

You need a CRL of atleast 25k, to have a corresponding OBC Rank of 5k. One of my mentees, secured 141 in JEE Main 2020, to end up with 97.1 percentile and 30k AIR. Hence, for 25k, you must target anywhere between 140-145/300.

For more information about JEE Main do

Dear aspirant,

For jee mains 2021 i can give you only predictions according to my calculations you need to score a minimum of 180+ to get cse or electronic and communication in nit Durgapur . 180+ would be sure for you to confirm your seat and also.you would have the