National Institute of Technology Karnataka Surathkal
Hi Ansar,
The question you have asked is a bit confusing so it would be better if you can elaborate your question we can answer properly and it will benefit you.
Thanks!!
Hiii
As per your marks your rank will be around 6.5k-7k(general). And if that is the case,for this rank you may not get CSE in nit surathkal as the closing rank is 5173 previous year.
You can check the previous year closing rank cutoffs in the following link
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-surathkal?amp
Hi Spoorthi, This is the procedure for admissions in NIT, Surathkal.
The B. Tech admission is through the JEE (Mains) test, and ranks are based on 60% of the marks scored in the test, and 40% in the class 12/Second PU Board exams.
Undergraduate admissions were based on a state-wise
Dear student,
For admission in NIT Surathkal (acc. to your question's tag) the minimum rank required for OBC category is nearly equal to 9000-9500 in B. Tech program of Mining engineering.
For that rank, approx. 96.5% + is required which further account to the marks required would be around 110-
You are advised to try for state Govt colleges and the private colleges which accept JEE MAIN rank as these are the only options available.
Good Luck!!!
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