National Institute of Technology Puducherry Karaikal
Hey!
There are no chances to get admission in National Institute of Technology (NIT) with this percentile. However, you can check out the list of colleges for which you are, using the link given below
https://engineering.careers360.com/jee-main-college-predictor
Thank you.
Hello Aspirant,
As per the previous year NSR mop Up round you can have the chance to get National Institute of Technology Arunachal Pradesh, National Institute of Technology Nagaland- M.tech CSE programme.
You can check your other admission possibilities with GATE college predictor tool given below.
https://engineering.careers360.com/gate-college-predictor
Good Luck!
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 46144. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.
The cut offs for previous years for various branches at NIT Puducherry for Other State Candidates has been as follows:
Civil: 9307
CSE: 4627
ECE: 6263
me: 8352
EEE: 8127
So with your rank even with OBC reservation, NIT Puducherry might be tad less. You might have to appear for April session.
You haven't mentioned your Home State to analyse your other options. This is because the cut off ranks are different for Home State Candidates and other State Candidates. Please do help us with your Home State. Meanwhile, now to predict colleges, please use our college predictor: https://engineering.careers360.com/jee-main-college-predictor
One can qualify for JEE Advanced only after he clears JEE Mains Exam.
This year 869010 students have given the JEE Mains Exam in January .
So, you can calculate your rank by using the formula given below
(100-your total percentile)X 869010/100
Therefore, your overall rank will be between 155000-200000.
The last year cutoff was :
Civil Engineering - 9307 for other state and 96543 for home state
Computer Science and Engineering - 4627 for other and 56009 for home state
Electronics and Communication Engineering - 6263 for other and 66048 for home state
Mechanical Engineering - 8352 for other and 81971 for home state
Electrical and Electronics Engineering - 8127 for other and 96113 for home state
However, you can go through the below link for full cutoff according to your category and rank.
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-puducherry
According to last year cutoff , you are not eligible for NIT karaikal . I insist you to study and score more marks in JEE Mains April exam .
Let's wait for the final result which will be released by NTA after april exam .
You can also use our college predictor by using the link given below
The exact prediction would be difficult regarding your admission possibilities based on your percentile. But based on this percentile the chances seems less to qualify the exam as General category or get a seat in NITs, IIITs & GFTIs.
You can try for the state level counselling. I would also suggest you to appear for JEE Main April Session 2020 which application form is expected to start from 7th February, 2020.
To know your admission possibilities in state level counselling you can use JEE Main college predictor tool given below.
https://engineering. careers360.com/jee-main- college-predictor
Hello,
You have the chances to get a seat in nit. Also you are eligible for the jee advance. But now you should wait for the state counselling.
For more details you can use the following link
Hope for the best.
Hello! As you have not given the branch about which you want to know, I'll give you a rough idea about the cut off trends of last year. In 2019, the trends were:
Civil Engineering for general: AI-31813/ HS - 246946
CSE: AI- 15164/ HS- 134522
ECE: AI- 19231/ HS- 166930
ME: AI- 25044/ HS- 188436
Electrical and Electronics Engineering: AI- 26479/ HS - 217380
For last year cut offs and cut offs for other categories refer to our link: https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-puducherry/amp#aoh=15788856927604&referrer=https%3A%2F%2Fwww.google.com&_tf=From%20%251%24s
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