National Institute of Technology Rourkela
Dear Aspirant,
as you are well aware that the cutoff for each year varies depending upon various reasons, however based on the cutoff for the previous years given below are some of the colleges where you can apply for admission as per your score in GATE ,
To view the complete list of colleges as per the cutoffs for the current year, kindly visit the link given below.
https://engineering.careers360.com/gate-college-predictor
Hello,
It would be difficult to predict the cut off for CSAB 2021 round as the cut off depends on the total number of seats available after JoSAA round, total number of candidates participating in CSAB, difficulty level and other factors. So it is not possible to indicate the cut off prior to the counselling but here is the cut off in CSAB 2020 round 1 counselling for admission to Integrated Master of Science in Chemistry for NIT, Rourkela
Home state
Open state
All the ranks mentions are CRL ranks secured by the candidates belonging to the respective categories. The cut off is subjected to change, it may increase or decrease depending on total number of candidates applied, difficulty level of paper and number of seats available etc.
To check the cut off you can use the link provided
https://admissions.nic.in/csabspl/csabsplresult/result/CurrentORCR.aspx
To know the colleges in which you may get seat you can use our JEE Main college predictor
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Hi
Your profile suggests that your home state is Telangana so you will be eligible for other state quota in NIT Rourkela
With 96.25 percentile
your rank will be around 38362 - 43125 as per our rank predictor at https://engineering.careers360.com/jee-main-rank-predictor
It is quite difficult to make prediction but yes as per past year trend , you hold a little low chance to get a seat in NIT Rourkela for Chemistry (5 Years, Integrated Master of Science) .
For example,
In 6th round of josaa counselling 2020, closing rank for gender-neutral for general category was 36585 for Chemistry (5 Years, Integrated Master of Science) for gender neutral general category for other state
You can check the same at
https://josaa.nic.in/Result/Result/currentorcr.aspx
Above prediction is on the basis of past year data but cut off/closing rank for colleges keeps changing every year depending upon many factors like number of students that appeared in the examination, difficulty level of the JEE main question paper for different shifts etc so
To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you
Thankyou
Hello aspirant,
Its costs around 90000-100000 per annum but you will get scholarship too.
Fee is different for different streams of M.sc(varies lillte bit).
Scholarship is based on the rank and caste category.
Hope this helps you
All the best for your future
hello aspirant,
As of now it's tough to say what could be the cutoff because every year the cutoff changes due to many factors like total students appearing for exam, difficulty level of paper etc factors.but based on previous year analysis and your rank, category we can help you with your query.now as you did not mention your category considering you from GEN category below are the admission cutoffs by ranks for different branches of NIT rourkela:
cse :home state-10349,other state-4115
ece :home state-12594,other state-5674
eee :home state-21534,other state-9875
civil engg :home state-27403,other state-17939
mechanical engg :home state-21464,other state-11825
chemical engg :home state-30308,other state-18067
note that each year the cutoff varies due to many factors like total students appearing for exam,dificulty level of paper etc so if cutoff changes so are your chances into colleges.to get the list of cutoffs for all the branches and other categories refer to: https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-rourkela
hope this helps,
thankyou.
You have got around 43000 rank in jee mains in general category and around 1540 rank in ews category. Yes, there is high possibility that you can get Nit rourkela under ews category. At ews category, you can get all branches as the qaulify its cutoff.
but you can also predict your best college at that rank by use of college predictor tool.
use this link
Dear aspirant,
As you have got 93.5 percentile in your feb session and considering you as an obc category candidate ,there is very less chance to get into any branch in nit Rourkela as the cut offs for this college are very high . So I would recommend you to increase your percentile in your next attempts so that you can get your desired college.
For college prediction kindly follow the link given below-
Hello Candidate,
Nowadays, the JEE Mains examination is held in different shifts and sessions and each of the sessions have a different question paper and hence, rather than the marks the Percentile plays an important role for final selection into the colleges apart from your category.
So, if you are some general category and have scored a percentile above 95, then there are chances that you would get admission into some streams. For more details, visit https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-rourkela/amp
Hope it helps!!
JEE Main 2019 cut off for ECE in NIT Rourkela was:
Home state general: 12594
Home state EWS: 1699
All India General: 5674
All India EWS: 618
So, judging from previous year cut off, you need to score more than 135-140 marks in JEE Main.
Hope it helps!
Good luck!
Hello Dear,
Cutoff for EWS male category was 1241 rank in NIT Rourkela. NIT Rourkela offers BTech, BTech-MTech (Dual Degree), Integrated MSc and BArch programmes. Candidates seeking admission to 5 years Full-time B.Arch Program should have passed 12th or equivalent examination with a minimum aggregate of 50% marks with Mathematics and English as compulsory subjects of study. For more details you can visit the link:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-rourkela
Good Luck
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