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National Institute of Technology Silchar

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I got 161527 rank in ap eamcet 2024 can I get CSE branch

kumardurgesh1802 24th Aug, 2024

Hello student,

With a rank of 161,527 in AP EAMCET 2024, getting a seat in the CSE branch in top-tier colleges might be challenging. However, you may still have chances in some private colleges or lower-tier institutions. Here’s what you can consider:

Possible Options:

  1. Private Engineering Colleges:

    a) Colleges in Rural Areas: Some private colleges in less competitive areas may offer CSE seats at this rank.

    b) Management Quota: Consider looking into management quota seats if the general quota is not available.

  2. Less Popular Colleges: Colleges that are relatively new or have lower demand may still offer CSE seats.

  3. Alternative Branches: If CSE is not available, you might consider closely related branches like IT (Information Technology) or ECE (Electronics and Communication Engineering).

Your chances of getting a CSE seat in top colleges are slim, but you might still secure a spot in some private or lesser-known institutions. It’s advisable to keep an eye on the counseling process for seat availability and be flexible with college and branch options.


I would recommend you to use AP EAMCET college predictor tool by Careers360 to get the list of possible colleges you can get with your rank.

Here is the link to the tool:

https://www.careers360.com/ap-eamcet-college-predictor?utm_source=qna&utm_medium=ini-cet_cp

Click on the above link, fill the required details and you will get the list of possible colleges at your rank.


I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.

135 Views

I get 81.12 percentile can get nit silchar in sc category

shivamtrivedi0005 24th Feb, 2024

Hii There,

Based on the analysis of marks versus percentile versus rank for JEE-Main 2020, your Common Rank List (CRL) rank is estimated to fall between 306900 and 345000. You can review the relationship between marks, ranks, and percentiles by referring to the provided link.-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

To have a list of all those colleges which you can get based upon your marks, category, and state you can use JEE-Main College Predictor:-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

I hope this information helps you.

Good Luck!!

26 Views

jee mains percentile 81.1206661 can get Nit silchar with sc category

Satvik 5th Oct, 2024

Hi

hope you doing well

Whilw having a score of 81.12% in Jee mains, and belonging to the S C category, you have a chance of getting admission into NIT Silchar under the SC quota. The cutoffs for SC candidates are generally lower than those for the General category.

However, admission to specific branches like CSE or ECE might still be challenging, as these branches have higher cutoffs. You are more likely to secure a seat in branches like Mechanical, Civil, or Electrical Engineering.

The exact cutoffs vary year by year, but based on previous trends, your percentile puts you in contention for certain branches.

You can prefer Josaa counseling for more options

you can colleges as per your rank through tis link:

JEE College Predictor

https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp

Best Wishes.

119 Views

Question : Directions: In a certain code language, BOUCLE is coded as AJYSKZ. What is the code for BOUDIN in that code language?

Option 1: JGGSKZ

Option 2: JGZKSZ

Option 3: JGZSKZ

Option 4: JGJSKB

Team Careers360 25th Jan, 2024

Correct Answer: JGZSKZ


Solution : Given:
BOUCLE is coded as AJYSKZ.

Subtract 2 and 4 alternatively in the place value of each letter of BOUCLE and write the letters in reverse order, to get the required code. –

Thus, BOUCLE is coded as AJYSKZ.
Similarly, follow the same pattern for BOUDIN –

So, BOUDIN is coded as JGZSKZ. Hence, the third option is correct.

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