National Institute of Technology Tiruchirappalli
Hello Ratan
As you know that Cutoff's are still not released as the second phase exam is still left but you can use our college predictor's link : https://engineering.careers360.com/percentile-predictor-result/1094?s=39600026441548134962
You can also use this link for more information on cutoff's : https://engineering.careers360.com/articles/jee-main-cutoff
Hello aspirant,
Based on previous year ranking and making strategies,for getting a seat in NIT Thrichi, about 98 percentage is required.And a rank nearly 1500 is required to get into the best NIT of India, which is NIT Thrichi. Hope this will help you.
Good luck
Hello Vikram
Fee Structure for B.Tech programme (2018-19) in NIT Tiruchirappalli was 66850. You can go through the link below to check the detailed fee structure
https://www.nitt.edu/home/admissions/Institute-fees-Structure-Old-Sem-2018.pdf
Good Luck!
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Hello Sumit,
Thanks for contacting Careers360.
Congratulating you for your score.
With this much percentile there are decent chances that you will get a seat in NIT, Tiruchirapalli.
But in order to know your final result and the colleges you will get in that rank, you have to wait as
Dear Sami,
If you have 93 percentile means you should have a rank of about 83000. If you have a rank of this range then you can get into the following courses in NIT Trichy, just go to the link given below:-
Link - https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-trichy
I hope that helped you!
Hello aspirant. Thanks for connecting with Careers360. I would like to tell you that the final cutoff has not been released yet by NTA. I am sharing a link with you which consist of previous year cutoffs. You can get an estimate from it.
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
I hope this answer helped
Hello,
With this percentile your rank is between 70,000-75,000 in OBC category and for getting admitted in NIT Tiruchirappalli your rank is must be 9,000 approx so,I don't think that you can be able to get admission in NIT Tiruchirappalli.
Best of luck !!
Hello Akash
Congrats for scoring 94.27 percentile in JEE mains 2019
From the given percentile There is a pedicted formula from our team to predict rank
Total No of students =874469
Formula
Probable Rank= ( 100 - your NTA percentile ) x 874469 / 100
So your predicted rank =
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