Hello Chaitanya!

Admission to general degree programs like B.Com (//B.Com) . (Hons.) is provided by Nirma University, Ahmedabad on the basis of merit of the candidates in the last qualifying examination.

-The aggregate % of marks / CGPI obtained in Class 12 ^th Board Exams (or its equivalent) is used

Hi there,

Your percentile is not good enough for nirma university to get a good branch in the college.

However if you want to apply for the counselling then fill the online form for counselling through the college portal.

I hope this help

Hello dear

As I can see the past year results you need to secure rank under 20000-22000 ( or may be better  ) for getting admission in computer science in nirma university and for this you must require a percentile greater than 98 . It may vary according to the

Hello,

According to JEE Mains 2019 the closing ranks for EC in Nirma University was 203.For second round of counselling the closing rank was 321.There might be slight variations in the closing ranks every year.Check out the link below to know more about the same :

https://engineering.careers360.com/articles/nirma-university-btech-admissions

Hello aspirant,

According to previous year's cut-off trends, to get admission in Nirma University for BTech in Computer science you will need to get a rank below 25000 in JEE Mains 2020. Below is the 2018 cut-off for Nirma University for computer science engineering:

Hello Aspirant,

The tuition fees of Nirma University is Rs. 40000 for PH.D full time course. You can check the complete fees structure to go through with the given below link.

https://fdsr.nirmauni.ac.in/admission-aid/doctor-of-philosophy/full-time-phd-program/

As per the procedure admission, The Entrance Test shall be conducted for eligible candidates wherein the qualifying marks

Hello !

Last year cut -off of Nirma University as you have tagged this college , is 96 for round 1 and 174 for round 2 , for admissions in Computer Science. So from this data you can expect this year percentile for getting admission.

You can check more on