Physics
Hello Harsh Jindal..
According to careers360 rank formula,
Rank formula= [(100-total score) * (no of students wrote exam)] /100
No of students attended are 874469.
So your expected rank will be nearly around 5,33,627.
As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.
Yes , definitly you will get admission in any of these , your rank will be around 150 -200
HELLO MINDUL!
First of all above score is not your raw score of subject,that is percentile score.And your total percentile score is 5.876.Percentile score only states about relative performance of candidates in their respective session.Don't worry you still have one attempt for jee main 2019.Best of two percentile score will
Hello Tushar Mote,
Yes, you are eligible.
Eligibility Criteria for JIMPER 2019 -
50% marks in aggregate in 12th class (40% marks for OBC/SC/ST/OPH and 45% marks for GEN-OPH) in PCB stream. Candidate should pass individually in each subject.
Thanku.
JEE Main 2019 is being conducted twice by NTA for the first time and the rank will be based on NTA percentile so the exact prediction would be difficult about the qualify score or rank.
Based on this score your probable rank will be 580,134 - 645,134 and your probable
Hello
Percentile of candidate in Physics is calculated using the below formula-
100 X No. of candidates appeared from the session with raw score EQUAL TO OR LESS than P1 score in Physics/Total No. of candidates appeared in the session
You can go through the link below and check the
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