Physics
Hello Shashank,
Maximum velocity occurs at the mean position in the simple harmonic motion -
So K.E at the centre= 9-5 = 4J
=>1/2mv^2 = 4 => V(max) =2m/s
In SHM V(max) = AW where A=1 in the given problem =>W=2 =>f=3.14 (f=2*3.14/W)
Hope this helps.
Practice and clear concept is the key to scoring good.
NCERT and other textbooks like coaching notes form the basic level of knowledge. Now to twist and apply the knowledge gained do MCQ. Physics Exemplar is a good book for clearing concepts but only 50% of chances are there in
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BSc is just a degree certificate that is not at all sufficient to gets job in TOP product based companies like especially Microsoft and Google. I'm sorry that I'm very straight forward because the competition is highly to get placed in top companies.
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