Hello Aspirant,

You may get these colleges

Computer Science Engineering

HIT - Haldia Institute of Technology, Midnapore - B.Tech. in Computer Science and Engineering (Cyber Security)

HIT - Haldia Institute of Technology, Midnapore

Netaji Subhash Engineering College

Information Technology

St. Thomas' College of Engineering and Technology - STCET

B.P. Poddar

Hello Aspirant,

You may get these colleges

Computer Science Engineering

AIET - Appa Institute of Engineering and Technology

PNS Institute of Technology

Vijaya Vittala Institute of Technology

Information Technology

SSIT - Sri Siddhartha Institute of Technology

Nadgir Institute of Engineering and Technology, Karnataka

Alva's Institute of Engineering and Technology

Electronics

Hey Aspirant,

As your rank is quite high. Here are previous year cut-off ranks for Sastra University Thanjavur campus :

For stream 1

CSE : less than 650

ECE: less than 800

EEE: 1100

Mech: 1100

ICT,IT: 1300

others below 2100 at max

But if you are from Tamilnadu state

Hello Aspirant,

According to the COMEDK 2022 rank mentioned by you in the question you have good chances in following colleges for CSE branch :-

Don Bosco Institute of Technology, Bangalore

Jain College of Engineering

KLE Technological University Hubballi, Belagavi Campus. (Formerly called as KLE Dr. M.S.sheshgiri college of Engineering

Hello aspirant,

Looking at the previous year COMEDK Cutoff, in order to get good and top colleges through COMEDK (like RVCE, BMSCE, MSRIT) you have to score a rank of within 1000-2000 for CSE. Otherwise for getting average and low ranked colleges through COMEDK, you have to get a rank

Hii

Sorry you can't eligible for admission in coep. I give you cuttoff.

Hey Aspirant,

As per your information you got 31 percentile in AEEE. And you belong to an open quota student don't have show that you belong to which open quota or state quota. Your rank between the range of 15000-19000. This is not accurate rank only predict rank. It may

Hello Aspirant

Making predictions is tricky because the KCET cut off depends on a variety of variables, including the number of students who took the exam, the type of marks they got, and how difficult the test was. The number of seats for each branch for the group to which

Hi, CHINNUHEMANTH373

Now we know that

Rank will be given according to the formula

R= {(%KCET+%QE)/200}×100

with 65 marks in KCET you're having a percentage of 36.11% ((65/180)*100)

& then in boards you have a percentage of 95 % ((285/300)*100)

adding both percentages you have a total of 95+36.11= 131.11