Correct Answer: Temin & Baltimore

Solution : The correct option is - Temin & Baltimore.

David Baltimore and Howard Temin independently and concurrently discovered reverse transcriptase in retroviruses (at the time, RNA tumor viruses), which revolutionized molecular biology and laid the groundwork for retrovirology and cancer biology in 1970. 

Correct Answer: 20 cm

Solution : Let length be L and breadth be B, 
Since the sides of the square are equal, 
⇒ L − 4 = B + 2 ...........(1) 
⇒ L = B + 6 
The area of the rectangle is equal to the area of the square, 

Correct Answer: 1 October

Solution : The correct option is 1 October.

The International Day for Older Persons is observed on October 1 each year. This day is dedicated to recognising and celebrating the contributions and achievements of older people in society. It also serves as an opportunity to raise

Correct Answer:

Solution : The correct answer is Trellis.

A Trellis Drainage Pattern is one in which tributaries come together at sharp angles, generally approaching straight angles. These form when sedimentary rocks are folded or inclined and subsequently eroded to varied degrees based on their strength.
Example- Satluj river follows

Correct Answer:

Eye

Solution : The correct option is the eye.

Mammalian eyelids, including human eyelids, have meibomian glands. These glands emit an oily material called meibum which prevents tears from evaporating off the surface of the eye. This oily layer also aids in the stability of the tear

Correct Answer: Sodium(Na)

Solution : The correct option is Sodium(Na).

Sodium is a highly electropositive element. It belongs to Group 1 of the periodic table, also known as the alkali metals group. Elements in this group, including sodium, have a single valence electron in their outermost energy level. When sodium

Correct Answer: $b^2-a^2$

Solution : $a \cot \theta+b \operatorname{cosec} \theta=p$
$b \cot \theta+a \operatorname{cosec} \theta=q$
So, $p^2-q^2$
= $(a \cot \theta+b \operatorname{cosec} \theta)^2 - (b \cot \theta+a \operatorname{cosec} \theta)^2$
= $a^2 \cot^2 \theta+b^2 \operatorname{cosec}^2 \theta + 2×a \cot \theta×b \operatorname{cosec} \theta$ – $(b^2 \cot^2 \theta+a^2 \operatorname{cosec}^2\theta+2×b \cot \theta×a \operatorname{cosec} \theta)$

Correct Answer: HTORW

Solution : Given:

SPANK → PSNAK

In the coded language,

S ⇔ P; A ⇔ N

Similarly, THROW will be coded as:

T ⇔ H; R ⇔ O

THROW → HTORW

Hence, the fourth option is correct.

Correct Answer: Mitrochondria

Solution : The correct answer is Mitrochondria.

The Mitrochondria is also known as the cell's powerhouse. Mitochondria are organelles found in every eukaryotic cell. They are in charge of turning food into energy in the form of ATP, the cell's primary energy currency.

Correct Answer: 2

Solution : Given: $a^{4}+1=\frac{a^{2}}{b^{2}}( 4b^{2}-b^{4}-1)$
⇒ $\frac{(a^{4}+1)}{a^2}=\frac{1}{b^{2}}( 4b^{2}-b^{4}-1)$
⇒ $a^2+\frac{1}{a^2}=4 -b^2-\frac{1}{b^2}$
⇒ $a^2+\frac{1}{a^2}+2+b^2+\frac{1}{b^2} +2 =0$
⇒ $(a-\frac{1}{a})^2+(b-\frac{1}{b})^2=0$
So, $(a-\frac{1}{a})^2=0 \;$and$\; (b-\frac{1}{b})^2=0$
⇒ $a-\frac{1}{a}=0 \; $ and$\; b-\frac{1}{b}=0$
⇒ $a=\frac{1}{a} \; $ and$\; b=\frac{1}{b}$
⇒ $a^2=1 \;$ and $\; b^2 = 1$
$\therefore a^{4}+b^{4}=2$
Hence, the correct answer