Staff Selection Commission Combined Graduate Level Exam
Question : Directions: The second number in the given number pairs is obtained by performing certain mathematical operation(s) on the first number. The same operation(s) is/are followed in all the number pairs except one. Find that odd number pair.
Option 1: 7 : 46
Option 2: 13 : 166
Option 3: 9 : 78
Option 4: 48 : 144
Correct Answer: 48 : 144
Solution : Let's check the options – First option: 7 : 46→(7)2 – 3 = 49 – 3 = 46 Second option: 13 : 166→(13)2 – 3 = 169 – 3 = 166 Third option: 9 : 78→(9)2 – 3 = 81
Question : The area of triangle formed by the straight line $3x + 2y = 6$ and the co-ordinate axes is:
Option 1: 3 square units
Option 2: 6 square units
Option 3: 4 square units
Option 4: 8 square units
Correct Answer: 3 square units
Solution : The area of a triangle formed by a line and the coordinate axes $=\frac{1}{2} \times \text{base} \times \text{height}$ The line $3x + 2y = 6$ At $y = 0⇒x = \frac{6}{3} = 2$ At $x = 0⇒y = \frac{6}{2} = 3$ So, the
Question : If $\left(y+\frac{1}{y}\right)=4$, then find the value of $\left(y^6+\frac{1}{y^6}\right)$.
Option 1: 2702
Option 2: 2704
Option 3: 4096
Option 4: 2706
Correct Answer: 2702
Solution : Given: $\left(y+\frac{1}{y}\right)=4$ Squaring both sides, we get ⇒ $\left(y+\frac{1}{y}\right)^{2}=4^{2}$ ⇒ $y^{2}+\frac{1}{y^{2}}=16-2$ ⇒ $y^{2}+\frac{1}{y^{2}}=14$ Cubing both sides, we get ⇒ $(y^{2}+\frac{1}{y^{2}})^3=14^3$ ⇒ $\left(y^6+\frac{1}{y^6}\right)+3×\left(y^2×\frac{1}{y^2}\right)×\left(y^2+\frac{1}{y^2}\right)=2744$ ⇒ $\left(y^6+\frac{1}{y^6}\right)+3×14=2744$ ⇒ $\left(y^6+\frac{1}{y^6}\right)=2744-42$ $\therefore \left(y^6+\frac{1}{y^6}\right)=2702$ Hence, the correct answer is 2702.
Question : If $a+b+c$ = 6 and $ab+bc+ca$ = 11, then the value of $bc(b+c)+ca(c+a)+ab(a+b)+3abc$ is:
Option 1: 33
Option 2: 66
Option 3: 55
Option 4: 23
Correct Answer: 66
Solution : Given: $a+b+c$ = 6 and $ab+bc+ca$ = 11 To find: $bc(b+c)+ca(c+a)+ab(a+b)+3abc$ = $b^2c+bc^2+c^2a+ca^2+a^2b+ab^2+abc+abc+abc$ = $bc(a+b+c)+ac(a+b+c)+ab(a+b+c)$ = $(a+b+c)(ab+bc+ac)$ Putting the values, we get ⇒ 6$×$11 = 66 Hence, the correct answer is 66.
Question : Potato is a_____.
Option 1: root
Option 2: stem
Option 3: bud
Option 4: fruit
Correct Answer: stem
Solution : The answer is a stem.
Potato (Solanum tuberosum) is a starchy, edible tuber that is a modified underground stem, also known as a tuber. A tuber is an expanded storage structure used by plants to store nutrients. Potato plants grow underground and produce these tubers
Question : Directions: A watch company produces four different products. The sale of these products in lakhs during 2005 and 2010 is shown in the following bar diagram. Study the graph and answer the question.
The sales of table clocks in 2010 were less than the sales of wall clocks in 2010 nearly by:
Option 1: 70.5%
Option 2: 69.05%
Option 3: 68.05%
Option 4: 62.05%
Correct Answer: 69.05%
Solution : As per the given graph, The sales of table clocks in 2010 = 9.5 lakh The sales of wall clocks in 2010 = 30.7 lakh The required percentage = $\frac{30.7-9.5}{30.7}$ × 100 = $\frac{21.2}{30.7}$ × 100 = 69.05% Hence, the correct answer is 69.05%.
Question : An electronic store owner allows two successive discounts of 20% and 25% on each item. The store has a reward points scheme that enables a customer to get free shopping worth INR 0.10 on every 1 reward point credited to the customer's account on previous purchases from the store. A customer decides to buy a laptop that is marked at INR 72,000. What will be its net selling price if he has 2850 reward points to his credit?
Option 1: INR 43,200
Option 2: INR 42,915
Option 3: INR 42,215
Option 4: INR 42,942
Correct Answer: INR 42,915
Solution : The first discount is 20% on the marked price. Price after the first discount = 80% × marked price = 0.8 × 72,000 = INR 57,600 The second discount is 25% on the price after the first discount. Price after the second discount =
Question : Find the Simple Interest on INR 27,000 at $14 \frac{2}{3}$% per annum for 8 months.
Option 1: INR 2,600
Option 2: INR 2,630
Option 3: INR 2,610
Option 4: INR 2,640
Correct Answer: INR 2,640
Solution : Given: Principal = INR 27,000 Rate of interest = $14 \frac{2}{3}$% Time period = 8 months = $\frac{8}{12}=\frac{2}{3}$ year. Simple interest = $\frac{\text{Principal × Rate × Time}}{100}$ = $\frac{27000×\frac{44}{3}×\frac{2}{3}}{100}$ = 60 × 44 = INR 2,640. Hence, the correct answer is INR 2,640.
Question : Match the animals in column A with the phylum they belong to in column B
Option 1: i-a, ii-c, iii-b, iv-d
Option 2: i-d, ii-a, iii-b, iv-c
Option 3: i-a, ii-b, iii-c, iv-d
Option 4: i-d, ii-c, iii-b, iv-a
Correct Answer: i-d, ii-c, iii-b, iv-a
Solution : The correct option is i-d, ii-c, iii-b, iv-a.
Jellyfish belong to the phylum Cnidaria (Coelenterate), Crayfish belong to the phylum Arthropoda, Whales belong to the phylum Chordata (Mammal), and Devil Fish or Giant Squid belong to the phylum Mollusca.
Question : The ratio of the radii of the two cones is 5 : 6 and their volumes are in the ratio of 8 : 9. The ratio of their heights is:
Option 1: 32 : 25
Option 2: 25 : 32
Option 3: 27 : 20
Option 4: 20 : 27
Correct Answer: 32 : 25
Solution : The volume of the cone = $\frac{1}{3}$πr2h, where r is the radius and h is the height. Let the radius of one cone be 5r and 6r. height is h1 and h2 ⇒ $\frac{1}{3}$(π × 25r × h1
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update
