All Questions

Staff Selection Commission Combined Graduate Level Exam

Follow
Showing 7691 - 7700 out of 16734 Questions
9 Views

Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".

Could she cite (1) / any precedent in support (2) / for her case? (3) / No Error (4)

Option 1: 1

Option 2: 2

Option 3: 3

Option 4: 4

Team Careers360 23rd Jan, 2024

Correct Answer: 3


Solution : The error lies in the third part of the sentence.

Explanation: The preposition "for" is incorrect in this context. When talking about supporting something, the correct preposition to use is "of". The term "in support of" means strengthening something.

Hence, the correct sentence should be:

12 Views

Question : Direction: In each of the following question, which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?

SH _ ELAS _ EELA _ HEELASHEE _ A

Option 1: HHSS

Option 2: EEHS

Option 3: EHSL

Option 4: ELHA

Team Careers360 25th Jan, 2024

Correct Answer: EHSL


Solution : Given:

SH _ ELAS _ EELA _ HEELASHEE _ A

We have to check the order of the letters in the given series.

To fill the series we have to divide the series, SH _ / ELA / S _ E/ ELA / _  HE

19 Views

Question : If $y+\frac{1}{y}=11$, then the value of $y^3-\frac{1}{y^3}$ is:

Option 1: $345 \sqrt{13}$

Option 2: $360 \sqrt{13}$

Option 3: $352 \sqrt{13}$

Option 4: $368 \sqrt{13}$

Team Careers360 15th Jan, 2024

Correct Answer: $360 \sqrt{13}$


Solution : Given, $y+\frac{1}{y}=11$
Squaring both sides, we get:
$⇒(y+\frac{1}{y})^2=11^2$
$⇒(y-\frac{1}{y})^2+4(y)(\frac{1}y)=121$
$⇒(y-\frac{1}{y})^2+4=121$
$⇒(y-\frac{1}{y})^2=121-4$
$⇒(y-\frac{1}{y})=3\sqrt{17}$
Cubing both sides, we get:
$⇒(y-\frac{1}{y})^3=(3\sqrt{17})^3$
$⇒y^3-\frac{1}{y^3}-3(y)(\frac{1}{y})(y-\frac{1}{y})=351\sqrt{13}$
$⇒y^3-\frac{1}{y^3}-3(3\sqrt{17})=351\sqrt{13}$
​​​​​​$⇒y^3-\frac{1}{y^3}=351\sqrt{13}+9\sqrt{13}$
$\therefore y^3-\frac{1}{y^3}=360\sqrt{13}$
Hence, the correct answer is $360\sqrt{13}$.

18 Views

Question : Directions: In a certain code language, if PDFJARS is written as OCELZQR and MHCXBTU is written as LGBZAST, how will ZVDGENQ be written in the same code language?

Option 1: XUYCIMP

Option 2: YUCIDMP

Option 3: XUCDEMQ

Option 4: XVDEDNO

Team Careers360 25th Jan, 2024

Correct Answer: YUCIDMP


Solution : Given:
PDFJARS is written as OCELZQR.
MHCXBTU is written as LGBZAST.

Subtract 1 from the place values of the letters except the middle one; add 2 to the place value of the letter in the middle of the given word.
Like, PDFJARS→P – 1 =

13 Views

Question : Directions: In the question, a part of the sentence is in bold. Below are given alternatives to the bold part at (1), (2), and (3) that may improve the sentence. Choose the correct alternative. In case no improvement is needed, your answer is (4).

They prevented me from danger.

(1) was preventing

(2) were preventing

(3) protected

(4) No Improvement

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 25th Jan, 2024

Correct Answer: (3)


Solution : The sentence can be improved using the third option "protected".

It conveys the idea that they kept the speaker safe from danger. "Protected" is the past tense of "protect", which fits the context of the sentence. "Prevent" means to avoid or avert a negative situation,

18 Views

Question : The volume of a solid hemisphere is 19404 cm3. Its total surface area is:

Option 1: 4158 cm2

Option 2: 2858 cm2

Option 3: 1738 cm2

Option 4: 2038 cm2

Team Careers360 14th Jan, 2024

Correct Answer: 4158 cm2


Solution : Given: Volume of solid hemisphere = 19404 cm3
Let the radius of the hemisphere be $r$.
We know, volume of a hemisphere $= \frac{2}{3}\pi r^3$
$⇒ 19404 = \frac{2}{3}\pi r^3$
$⇒ 19404 = \frac{2}{3}\times\frac{22}{7}\times r^3$
$\therefore r= 21$
Total surface area of

17 Views

Question : Which of the following statement(s) is/are TRUE?
I. $\sqrt{11}+\sqrt7<\sqrt{10}+\sqrt8$
II. $\sqrt{17}+\sqrt{11}>\sqrt{15}+\sqrt{13}$

Option 1: Only I

Option 2: Only II

Option 3: Both I and II

Option 4: Neither I nor II

Team Careers360 14th Jan, 2024

Correct Answer: Only I


Solution : Evaluating the given statements:
I. $\sqrt{11}+\sqrt7<\sqrt{10}+\sqrt8$
Squaring both sides we get:
⇒ $(\sqrt{11}+\sqrt7)^2<(\sqrt{10}+\sqrt8)^2$
⇒ $11+7+2\sqrt{77}<10+8+2\sqrt{80}$
⇒ $18+2\sqrt{77}<18+2\sqrt{80}$
So, statement I is true.
II. $\sqrt{17}+\sqrt{11}>\sqrt{15}+\sqrt{13}$
Squaring both sides we get:
⇒ $(\sqrt{17}+\sqrt{11})^2>(\sqrt{15}+\sqrt{13})^2$
⇒ $17+11+2\sqrt{187}>15+13+2\sqrt{195}$
⇒ $28+2\sqrt{187}>28+2\sqrt{195}$
So, statement II is wrong.
Hence, the correct answer

8 Views

Question : Directions: A series is given below with one term missing. Choose the correct alternative from the given ones that will complete the series.
A, E, I, M, ?

Option 1: P

Option 2: Q

Option 3: R

Option 4: O

Team Careers360 17th Jan, 2024

Correct Answer: Q


Solution : Given: 
A, E, I, M, ?

The pattern followed here is –
A + 4 = E; E + 4 = I; I + 4 = M
Similarly, M + 4 = Q

Q is the missing term of the given series. Hence, the second

The question have been saved in answer later, you can access it from your profile anytime. Access now