Staff Selection Commission Combined Graduate Level Exam
Question : A man bought 30 defective machines for INR 1,000. He repaired and sold them at a rate of INR 300 per machine. He made a profit of INR 150 per machine. How much did he spend on repairs?
Option 1: INR 5,500
Option 2: INR 4,500
Option 3: INR 3,500
Option 4: INR 2,500
Correct Answer: INR 3,500
Solution : The cost price of 30 defective machines = INR 1,000 The selling price of 1 machine = INR 300 Total selling price = INR 300 × 30 = INR 9,000 Profit per machine = INR 150 Total profit = INR 150 × 30 =
Question : In Chola administration,________ was the assembly in the villages which were inhabited predominantly by the Brahmanas.
Option 1: Ur
Option 2: Khilya
Option 3: Nagaram
Option 4: Sabha
Correct Answer: Sabha
Solution : The correct option is Sabha.
In the Chola administration, the assembly in villages predominantly inhabited by Brahmanas was known as the Sabha. These assemblies played a significant role in the governance and local administration of Chola society, and they were responsible for various local matters
Question : When Granite rocks get metamorphosed, they form
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : The correct answer is Gneiss.
Gneiss is a metamorphic rock of high grade, which means it has been subjected to high temperatures and pressures. It is generated as a result of the metamorphism of granite or sedimentary rock. Gneiss has distinct foliation, which represents alternating layers
Question : Directions: If a mirror is placed on line AB, which of the answer figures is the right image of the given figure?
Solution : As per mirror image properties, closer things appear close to the mirror in reflection. According to the information provided, if the mirror is placed on the right side of the figure (on line AB), the right of the reflected image will appear as the left, and
Question : If $x+3y=-3x+y$, then $\frac{x^{2}}{2y^{2}}$ is equal to:
Option 1: $\frac{1}{8}$
Option 2: $\frac{1}{2}$
Option 3: $\frac{1}{4}$
Option 4: $4$
Correct Answer: $\frac{1}{8}$
Solution : Given: $x+3y=-3x+y$ Solution: ⇒ $x+3y+3x-y=0$ ⇒ $4x+2y=0$ ⇒ $2(2x+y)=0$ ⇒ $2x+y=0$ ⇒ $y=–2x$ Put the value of $y$ in $\frac{x^{2}}{2y^{2}}$ = $\frac{x^{2}}{2(–2x)^{2}}$ = $\frac{x^{2}}{8x^{2}}$ = $\frac{1}{8}$ Hence, the correct answer is $\frac{1}{8}$.
Question : If $\cot A=1, \sin B=\frac{1}{\sqrt{2}}$, find the value of $\sin (A+B)-\cot (A+B)$.
Option 1: $1-\sqrt{2}$
Option 3: $0$
Option 4: $1$
Correct Answer: $1$
Solution : $\cot A = 1= \cot 45°$ $\therefore A = 45°$ $\sin B = \frac{1}{\sqrt{2}}=\sin45°$ $\therefore B = 45°$ $\sin (A+B) = \sin 90° = 1$ $\cot (A+B) = \cot 90° = 0$ $\therefore \sin (A+B) -\cot (A+B) =1-0= 1$ Hence, the correct answer is $1$.
Question : The volume of a hemisphere is $2425 \frac{1}{2} \mathrm{~cm}^3$. Find its radius. $\left(\right.$ Take $\left.\pi=\frac{22}{7}\right)$
Option 1: 12 cm
Option 2: 10 cm
Option 3: 10.5 cm
Option 4: 9.5 cm
Correct Answer: 10.5 cm
Solution : The volume of hemisphere = $2425 \frac{1}{2} \mathrm{~cm}^3$ Volume of Hemisphere = $\frac{2}{3} × \pi r^3$ ⇒ $\frac{2}{3} × \frac{22}{7} × r^3 = \frac{4851}{2} \mathrm{~cm}^3$ ⇒ $r^3 = 1157.63$ ⇒ $r = 10.5$ cm $\therefore$ The correct answer is 10.5 cm. Hence, the correct
Question : If $α$ is an acute angle, $\tan (4α − 50°) = \cot (50° − α)$, then find the value of $α$ (in degrees).
Option 1: 60
Option 2: 45
Option 3: 30
Option 4: 90
Correct Answer: 30
Solution : $\tan (4α − 50°)$ = $\cot (50° − α)$ = $\tan(90°–(50° − α))$ ⇒ $\tan (4α − 50°)$ = $\tan(90°–(50° − α))$ ⇒ $(4α − 50°) = 90°–(50° − α)$ ⇒ $4α − 50° = 40°+α$ ⇒ $3α = 90°$ ⇒ $α = 30°$ Hence,
Question : If $\left(x+\frac{1}{x}\right)=5 \sqrt{2}$, then what is the value of $\left(x^4+x^{-4}\right)$?
Option 1: 2542
Option 2: 2650
Option 3: 2452
Option 4: 2302
Correct Answer: 2302
Solution : Given: $\left(x+\frac{1}{x}\right)=5 \sqrt{2}$ Squaring both sides, we get, ⇒ $(x+\frac{1}{x})^2=(5 \sqrt{2})^2$ ⇒ $x^2+\frac{1}{x^2}+2=50$ ⇒ $x^2+\frac{1}{x^2}=48$ Again squaring both sides, we get: ⇒ $(x^2+\frac{1}{x^2})^2=48^2$ ⇒ $x^4+\frac{1}{x^4}+2=2304$ $\therefore x^4+\frac{1}{x^4}=2302$ Hence, the correct answer is 2302.
Question : The Veda which deals with the rituals is known as
Option 1: Rigveda
Option 2: Yajurveda
Option 3: Samaveda
Option 4: Atharvaveda
Correct Answer: Yajurveda
Solution : The correct answer is Yajurveda.
The Yajurveda is a detailed manual on how to carry out religious rites and ceremonies properly. The Yajurveda is the Veda of prose mantras; its name is derived from yajus, which means prose mantra, and veda, which means knowledge.
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