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Staff Selection Commission Combined Graduate Level Exam

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Question : The following sentence has been split into four segments. Identify the segment that contains a grammatical error.
Scarcely had I / started reading / the paper / then the doorbell rang.

Option 1: Scarcely had I

Option 2: started reading

Option 3: then the doorbell rang

Option 4: the paper

Team Careers360 25th Jan, 2024

Correct Answer: then the doorbell rang


Solution : The error lies in the third option.

The reason for the error is that then is not the appropriate conjunction to connect the two actions in this context.

When is the correct choice to indicate the immediate sequence of events, as scarcely

7 Views

Question : Rs.11,500 has to be divided between X, Y, and Z such that X gets $\frac{4}{5}$th of what Y gets and Y gets $\frac{2}{3}$rd of what Z gets. How much more does Z get over X (in Rs.)?

Option 1: 7200

Option 2: 1800

Option 3: 1170

Option 4: 2450

Team Careers360 25th Jan, 2024

Correct Answer: 2450


Solution : Given: Rs.11,500 has to be divided between X, Y, and Z such X gets $\frac{4}{5}$th of what Y gets and Y gets $\frac{2}{3}$rd of what Z gets.
Let Z get Rs. $p$.
From the question, Y will get $\frac{2p}{3}$ and X will obtain $\frac{2p}{3}×\frac{4}{5}=\frac{8p}{15}$
Also,

27 Views

Question : Directions: Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster.
ACCUSED : UCCASDE :: FACTORY : TCAFOYR :: DYNAMIC : ?

Option 1: YNMICAD

Option 2: DNYMACI

Option 3: ANYDMCI

Option 4: DANYMIC

Team Careers360 17th Jan, 2024

Correct Answer: ANYDMCI


Solution : Given:
ACCUSED : UCCASDE :: FACTORY : TCAFOYR :: DYNAMIC : ?

Here, the letters of the given words are being shuffled following a certain pattern as shown below –
ACCUSED : UCCASDE→

FACTORY : TCAFOYR→

Similarly, follow the same pattern for DYNAMIC→

So, ANYDMCI

127 Views

Question : The monthly income of a person was INR 12,000 and his monthly expenditure was INR 8,000. Next year, his income increased by 10% and his expenditure by 8%. Find the percentage increase in his savings.

Option 1: 10%

Option 2: 14%

Option 3: 12%

Option 4: 15%

Team Careers360 13th Jan, 2024

Correct Answer: 14%


Solution : Given: Monthly Income = INR 12000
Monthly Expenditure = INR 8000
Increase in income = 10%
Increase in expenditure = 8%
Solution: Savings before increase = 12000 – 8000 = INR 4000
Increase in income = 12000 + $\frac{10}{100}$ × 12000 = INR 13200
Increase

24 Views

Question : The expression $\frac{\cos ^4 \theta-\sin ^4 \theta+2 \sin ^2 \theta+3}{(\operatorname{cosec} \theta+\cot \theta+1)(\operatorname{cosec} \theta-\cot \theta+1)-2}, 0^{\circ}<\theta<90^{\circ}$, is equal to:

Option 1: $\frac{1}{2} \sin \theta$

Option 2: $2 \sin \theta$

Option 3: $\sec \theta$

Option 4: $2\operatorname{cosec} \theta$

Team Careers360 22nd Jan, 2024

Correct Answer: $2 \sin \theta$


Solution : $\frac{\cos ^4 \theta-\sin ^4 \theta+2 \sin ^2 \theta+3}{(\operatorname{cosec} \theta+\cot \theta+1)(\operatorname{cosec} \theta-\cot \theta+1)-2}, 0^{\circ}<\theta<90^{\circ}$
$=\frac{(cos^2\theta)^2-(\sin^2\theta)^2+2 \sin ^2 \theta+3}{(\operatorname{cosec} \theta+1+\cot \theta)(\operatorname{cosec} \theta+1-\cot \theta)-2}$
$=\frac{(cos^2+\sin^2\theta)(cos^2-\sin^2\theta)+2 \sin ^2 \theta+3}{[(\operatorname{cosec} \theta+1)^2-\cot^2 \theta]-2}$
$=\frac{cos^2+\sin^2\theta +3}{[\operatorname{cosec^2} \theta+1+2\operatorname{cosec \theta}-\cot^2 \theta]-2}$
$=\frac{4}{2+2\operatorname{cosec} \theta-2}$
$=\frac{4}{2\operatorname{cosec} \theta}$
$=2 \sin \theta$
Hence, the correct answer

9 Views

Question : Directions: In the following question, select the odd letter pair from the given alternatives.

Option 1: CD

Option 2: PR

Option 3: ST

Option 4: WX

Team Careers360 21st Jan, 2024

Correct Answer: PR


Solution : Let's check the options –
First option: CD; C + 1 = D
Second option: PR; P + 2 = R
Third option: ST; S + 1 = T
Fourth option: WX; W + 1 = X

So, the second option is different from the

29 Views

Question : (91 + 92 + 93 + ... + 110) is equal to:

Option 1: 4020

Option 2: 2010

Option 3: 6030

Option 4: 8040

Team Careers360 18th Jan, 2024

Correct Answer: 2010


Solution : First term, $a$ = 91
Last term, $l$ = 110
Number of terms, $n$ = 20
The sum of n terms of series = $\frac{n}{2}(a+l)$
The sum of 20 terms of series = $\frac{20}{2}(91+110)=10(91+110)=2010$
Hence, the correct answer is 2010.

19 Views

Question : A batsman scores 87 runs in the 21st match of his career. His average runs per match increases by 2. What was his average before the 21st match?

Option 1: 45

Option 2: 46

Option 3: 44

Option 4: 43

Team Careers360 23rd Jan, 2024

Correct Answer: 45


Solution : Let his average before the 21st match be $x$.
New average after 21st match = $(x + 2)$
Total runs before the 21st match = $20x$
Runs scored in the 21st match = 87
⇒ $x + 2$ = $\frac{87 +

8 Views

Question : Direction: In the given question, select the related letter from the given alternatives.

AG : IO :: EK : ?

Option 1: LR

Option 2: MS

Option 3: PV

Option 4: SY

Team Careers360 23rd Jan, 2024

Correct Answer: MS


Solution : Given:

AG : IO :: EK : ?

A + 8 = I ; G + 8 = O; 

Similarly, E + 8 = L ; K + 8 = R

Therefore, LR is the related word.

Hence, the first option is correct.

 

 

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