Staff Selection Commission Combined Higher Secondary Level Exam
Question : The table given below shows the number of aerated drinks - A, B, C, D-manufactured (in thousands) by a company over the years.
Which aerated drink has the highest manufacturing number from 2019 to 2022?
Option 1: D
Option 2: B
Option 3: A
Option 4: C
Correct Answer: A
Solution : Number of A manufactured from 2019 to 2022 = 250 + 200 + 260 + 275 = 985 Number of B manufactured from 2019 to 2022 = 200 + 230 + 210 + 175 = 815 Number of C manufactured from 2019 to 2022 =
Question : According to the Census of India 2011, what is the percentage of the rural population of India?
Option 1: 65.25%
Option 2: 70%
Option 3: 69%
Option 4: 68.8%
Correct Answer: 68.8%
Solution : The correct answer is 68.8%.
According to the 2011 Census, the rural population in India is 68.8% and the urban population is 31.2%. According to the census, Uttar Pradesh has the largest rural population in India and is also the most populous state in
Question : Directions: In the following question a series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series. 7, 14, 28, 56, (?)
Option 1: 84
Option 2: 112
Option 3: 124
Option 4: 92
Correct Answer: 112
Solution : Given: 7, 14, 28, 56, (?)
Let's apply the pattern – 7 × 2 = 14; 14 × 2 = 28; 28 × 2 = 56; 56 × 2 = 112
So, the missing number in the series is 112. Hence, the second option is
Question : Directions: In the following question, identify the diagram that represents the best relationship among the classes given below. Teacher, Painter, Dramatist
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : According to the general information, some teachers can be painters, some can be dramatists, and some can be neither painters nor dramatists. On the other hand, some painters can also be dramatists. So, all the three circles will overlap. Therefore, the Venn diagram is as follows
Question : The name of the Brahmin priest who later came to be known as Ramakrishna Paramahamsa is:
Option 1: Gadadhar Chattopadhyaya
Option 2: Dayanand Saraswati
Option 3: Shree Narayana Guru
Option 4: Narendra Nath Datta
Correct Answer: Gadadhar Chattopadhyaya
Solution : The correct answer is Gadadhar Chattopadhyaya.
Gadadhar Chattopadhyay was born to a Brahmin priest who became known as Ramakrishna Paramahansa. His spiritual name was Ramakrishna Paramahansa, and he is regarded as a 19th-century Indian mystic and saint who preached religious tolerance, the universality of
Question : If $u{_n}=\frac{1}{n}-\frac{1}{n+1}$, then the value of $u{_1} + u{_2}+u{_3}+u{_4}+u{_5}$ is:
Option 1: $\frac{1}{2}$
Option 2: $\frac{1}{3}$
Option 3: $\frac{2}{5}$
Option 4: $\frac{5}{6}$
Correct Answer: $\frac{5}{6}$
Solution : Given: $u{_n}=\frac{1}{n}-\frac{1}{n+1}$ We have to find the value of $u{_1} + u{_2}+u{_3}+u{_4}+u{_5}$. $u{_1}=1-\frac{1}{2}$ $u{_2}=\frac{1}{2}-\frac{1}{3}$ $u{_3}=\frac{1}{3}-\frac{1}{4}$ $u{_4}=\frac{1}{4}-\frac{1}{5}$ $u{_5}=\frac{1}{5}-\frac{1}{6}$ Now, $ u{_1} + u{_2}+u{_3}+u{_4}+u{_5} = 1-\frac{1}{2} + \frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}$ $=1-\frac{1}{6} =\frac{5}{6}$ Hence, the correct answer is $\frac{5}{6}$.
Question : If $(x-2)$ is a factor of $x^2+3Qx – 2Q$, then the value of $Q$ is:
Option 1: 2
Option 2: –2
Option 3: 1
Option 4: –1
Correct Answer: –1
Solution : Given: $(x-2)$ is a factor of $x^2+3Qx-2Q$. Since $(x-2)$ is a factor of $P(x)=x^2+3Qx-2Q$. Then, $P(2)=0$ So, $x^2+3Qx-2Q=0$ $⇒2^2+3Q\times2-2Q=0$ $⇒4+6Q-2Q=0$ $⇒4Q=-4$ $\therefore Q=-1$ Hence, the correct answer is –1.
Question : Directions: By folding the given paper, which of the following boxes cannot be made?
Solution : The opposite pairs of faces are as follows –
So, in the 3D view of dice, 1. Each face out of three faces in 3D view should be from the pair. 2. Two opposite faces cannot appear adjacently in the 3D view of a folded dice.
Question : In the women's category, which athlete won the bronze medal at the 2023 Asian 20 km Walking Championships held in Nomi, Japan?
Option 1: Manju Rani
Option 2: Priyanka Goswami
Option 3: Bhawna Jat
Option 4: Khushbir Kaur
Correct Answer: Priyanka Goswami
Solution : The correct option is Priyanka Goswami.
Priyanka Goswami secured the bronze medal in the women's category at the Asian 20 km Race Walking Championships 2023, which took place in Nomi, Japan.
Question : If p = – 0.12, q = – 0.01, and r = 0.015, then the correct relationship among the three is:
Option 1: q > p > r
Option 2: p > r > q
Option 3: p > q > r
Option 4: r > q > p
Correct Answer: r > q > p
Solution : Given: p = – 0.12, q = – 0.01, and r = 0.015 In the number line, the greatest value is r = 0.015 then q = – 0.01 and the least value is p = – 0.12 Thus, the order
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