Correct Answer: $70^\circ$

Solution :
Given that $O$ is the orthocentre of triangle $ABC$, and $\angle BOC = 110^\circ$
Join OF, OD, and OE.
In quadrilateral $AFOE,$
$\angle AFO =\angle AEO = 90^\circ$
$\angle FOE =\angle BOC = 110^\circ$ (Vertically opposite angle)
The sum of four angles of a quadrilateral

Correct Answer: Lack of opportunities 

Solution : The Correct Answer is-  Lack of opportunities 

There is a current income gap between classes because there was not enough employment created in a timely manner. The economic gap between the wealthy and the poor widens as more people lose their jobs. The

Correct Answer: Rs. 10580

Solution : As per the given chart,
The amount spent on food = 23% of 46000 = $\frac{23}{100}$ × 46000 = Rs. 10580
Hence, the correct answer is Rs. 10580.

Correct Answer: Tapeworm

Solution : The correct answer is Tapeworm.

Platyhelminthes, commonly known as flatworms, are a group of animals belonging to the Kingdom Animalia. Among them, tapeworms are a specific type classified under the class Cestoda. These creatures are recognised for their flat, ribbon-like bodies.

Correct Answer: LSUQ

Solution : Given:
HPRM is written as OWYT, and JRTO is written as QYAV.

Add 7 to the place value of each letter of HPRM to obtain the required code –
HPRM→H + 7 = O; P + 7 = W; R + 7 = Y; M

Correct Answer: Babur and Jahangir

Solution : The correct option is Babur and Jahangir.

Only two Mughal rulers penned autobiographies: Babur, the Mughal Empire's founder and the fourth emperor, Jahangir. The Baburnama, his autobiography, is a chronicle of his life and times. The fourth Mughal emperor, Jahangir

Correct Answer: 25.6°C

Solution : Total temperature for the first four days = 4 × 25°C = 100°C
Total temperature for the last four days = 4 × 25.5°C = 102°C
Total temperature for the week = 7 × 25.2°C = 176.4°C
Total temperature for the first and last four

Correct Answer: 3

Solution : According to the question, $x$ = $y$ = $z$
We can put $x$ at the place of $y$ and $z$.
Given equation:
$\frac{\left (x+y+z \right )^{2}}{x^{2}+y^{2}+z^{2}}$ = $\frac{(x+x+x)^2}{x^2+x^2+x^2}$
⇒ $\frac{\left (x+y+z \right )^{2}}{x^{2}+y^{2}+z^{2}}$ = $\frac{(3x)^2}{3x^2}$
⇒ $\frac{\left (x+y+z \right )^{2}}{x^{2}+y^{2}+z^{2}}$ = $\frac{9x^2}{3x^2}$
⇒ $\frac{\left (x+y+z

Correct Answer: CUP : VYR

Solution : Given:
AMY : TQA
YJZ : RNB

Here, AMY : TQA→A + 19 = T; M + 4 = Q; Y + 2 = A
And, YJZ : RNB→Y + 19 = R; J + 4 = N; Z + 2 = B

Correct Answer: PWZ : OUW

Solution : Given:
EKM : DIJ; LPT : KNQ

Subtract 1, 2, and 3 from the place value of the first, second, and third letters respectively, to obtain the second letter clusters.
EKM→E – 1 = D; K – 2 = I; M – 3