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1490 Views

i want to cancel my neet application and registered in to neet 2020 application i have already paid money to my neet application please requesting you to refund the amount

Manidipa Kundu Student Expert 9th Dec, 2019

hi,

see the fees of form filling can not be refunded if you dont want to give the exam, or you want to re register for the exam, if it found to be 1 or more duplicate form submitted by candidates, his or her candidature can be cancelled.

hope you

61 Views

Hi...I want to ask what is cut off for ug admission in st. Xaviers college Kolkata bsc economics??

Avishek Dutta 9th Dec, 2019

Hi,

To get admission in st Xavier's college in bsc economics u need to score 91% +  if you are a general category. And if you have statistics as additional subject (if you are from science background) it would help you. And having the subject economics doesn't matter much

Hope

61 Views

my percentile is 96.06 can i guess seat in iiit Hyderabad for csc or any top 5nit

Nihal Kumar Gupta Student Expert 18th Jan, 2020

Hi CPavithra,

you have secured a good percentile in JEE main exam, you rank would be approximately in between 37,000 to 40,000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score.

If you have

2 Views

What is the full form of CLAT PG?

Manashjyoti 9th Dec, 2019

CLAT PG is the short form of the Common Law Admission Test for Post Graduate. 

31 Views

i was not allotted any college in csab counselling plzz my fee will be refund Or any contact number give me plzz because directly csab counsellor ask me

Parvathi Ramachandran 26th Dec, 2019

Greetings !

Yes definitely your fee will be refunded since you have not been allotted a college. Your fee will refund in the same bank account from which you have made transactions, so you don't have to worry about it. It will reflect in your bank accounts very soon, for

64 Views

Bharti vidhyapeeth institute of Management and entrepreneurship development.rank in Pune fee and about placement

S. Saha Student Expert 18th Jan, 2020
Bharati Vidyapeeth's Institute Of Management And Entrepreneurship Development, Pune is a private institute and it is one of the top MBA colleges with top class infrastructure in India. It has been rated by AAA grade by Careers360. The placement for MBA programmes has been increased by 11% than the previous
34 Views

I am an M.A ,B.ed in english and my date of birth is 01.05.1989.am i eligible for this .

manisha.gupta 17th Dec, 2019

Hello Aspirant,

According to SSC CGL Eligibility criteria, any graduate candidates in the age group of 18 to 32 years are eligible for the exam However, the SSC CGL age limit & eligibility varies from post to post.

You can check the post wise eligibility to go through with the

296 Views

I am final year bsc biology group student. Am i eligible to fill the neet ug 2020 form?? if yes,which eligibility code should i choose?

ADITYA KUMAR Student Expert 9th Dec, 2019
Hello dear
Greetings!

You are eligible for neet provided you have got at least 50 % aggregate in pcb in your class 12th board examination from a recognized board if you belong to general category ; while it's only 40% aggregate in pcb for obc, sc and st categories ,
340 Views

hello i got 89.74 percentile in jee main 2020 .can i get nit or iiit?and iam obc category.what is my expected rank

Vishwaksen Gouda Student Expert 18th Jan, 2020
Hello shriman,
It's been good you have secured nice percentile of 89.74 in the jee main examination-2020 . So for this percentile your rank will be around 83065 approximately.
After catching of your rank it seems slight hard to grab a good NIT. and there are chances you to write
46 Views

a body of mass 60 kg is inside a lift of masses 940 kg and presses the button on control panel the lift start moving upwards with an acceleration 1.5 metre per second square if g is equals to 10 metre per second inverse -2 to the tension in the supporting cable is

Avishek Dutta 9th Dec, 2019
Let the mass of the lift is M
And the mass of the body be m
Now a be the acceleration of the lift
And g be the gravitational acceleration.
Now we have to find the tension .
Let the tension be T.
Hence T-(m+M)g=(m+M)a
T=(m+M)(g+a).
Now in the question
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