It's a Question of your Career!

Hi,

Well honestly speaking the chances for you to get a seat seems moderate and not sure. The rank that you have score might get uplifted due to your category and that is why it might be easy for you to get a seat but still the chances seems moderate

Hello!

Go through the following link to check out the best NIT colleges based on college ranking, reviews, and also cut off!

https://engineering.careers360.com/colleges/list-of-top-nit-colleges-in-india

It is better to search for the college based on your ranking instead of percentile which will give you better accurate results!

Hence, I will also give

Dear Rajan,

NIMCET i.e, National Institute of Technology Master of Computer Applications Common Entrance Test conducts entrance exam under National Institute of Technology (NIT). And details for the entrance exam NIMCET- 2020 are listed below:

Release notification dates- 1st week of march.

Application form filling date - 1st week of

Following are the last year's cutoff of JEE Main for the eligibility of JEE Advanced:

CRL              89.7548849+

Gen-EWS    78.2174869

OBC-NCL    74.3166557

SC                54.0128155

ST                44.3345172

PwD            0.11371730

As you can see there are very less chances of being you qualified for JEE Advanced. Now, you have a chance to appear

218 out of 300 are decent marks in JEE Main paper 2. Also if you expect that you will get some marks in drawing also, then you can expect a decent percentile in Paper 2. Scoring such marks, you can expect a decent good college (Have very good of getting

Hey Nishant,

Here is the list of some Universities and colleges in Uttar Pradesh which offer both B.Sc. + B.Ed. as dual degree course.

• Amity University, Noida.
• IFTM University
• Invertis University
• Mangalayatan University
• Sharda University
• Shri Venkateshwara University

To know more about the college click on below links

• https://www.careers360.com/university/amity-university-noida
• https://www.careers360.com/university/iftm-university-moradabad

Rank of a candidate is calculated by the formula :

Rank = (100-percentile score)*(Total no. of students appeared for the exam)/100.

As the no. of students appeared for JEE Main Jan slot are around 869000, your calculated rank will be around 92460. However, if the no. of students in April

HELLO DEPLATA

The NTA score is also known as percentile. The expected rank of your percentile for the january session comes out to be 5474756. It  is very difficult to predict the actual rank since it depends o various factors.The expected rank might change depending on the no of students