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69 Views

Hello Sir what are the chances of securing admission in All India Quota in Deemed Universities and Private Colleges and also Karnataka and Odisha State Ouota in Clinical Subjects .I have secured a rank of 12895 in NEET MDS Examination 2020 and I belong to the general category .

Sonali Sahu Student Expert 24th Feb, 2020

Hello,

Your rank is good and getting an admission might be bit tough due high competition. you have mentioned two states. you can use state quota of one state only and it depends on your domicile criteria.

here are the college names for suggestion:-

  1. Government medical College
  2. Nizam Institute of
53 Views

pay of post diploma dnb candidate?

priyanshi parekh 15th Jan, 2020

Hello Aspirant ,

You can check the below link and check the stipent.


https://medicaldialogues.in/news/health/hospital-diagnostics/hospital-told-to-pay-rs-20000-compensation-for-serving-bad-food-to-patient-61950?infinitescroll=1

135 Views

pay of post diploma dnb candidate?

Raj Aryan Sharma 15th Jan, 2020

Hi Uday.

The minimum stipend or pay that has to be paid to a post diploma Diploma of National Board (DNB) candidate should be 35,000 rupees or more, and for DNB Super Speciality candidates and FNB candidates the minimum stipend or pay is 41,000 rupees . (https://education.medicaldialogues.in/nbe-redefines-stipends-of-dnb-fnb-candidates)

76 Views

pay of post diploma dnb candidate?

LAKSHMI AMBIKA 15th Jan, 2020

Hello uday Dessai,

The pay of post diploma dnb candidates is 35,000+.

Hope this answer is useful.

84 Views

pay of post diploma dnb candidate?

Malini S N 15th Jan, 2020

The National Board of Examination has recently issued the revised guidelines for the stipend to be paid to Diplomat of National Board and FNB candidates pursuing their PG medical courses at various accredited hospitals/institutions across the country.In the 1st Year of training,you will be paid 35,000,in 2nd Year 37,000 and

143 Views

i have scored 133 in 9 january shift 2 2020 what is my expected percentile

Aishwarya Kadam 15th Jan, 2020

Hi,

Based on your JEE Mains marks you can expect a overall percentile of around 98.18-98.38. Your general rank can be around 14765-16915.

You can check out the JEE Mains percentile and rank predictor:

https://engineering.careers360.com/jee-main-rank-predictor?icn=JEE_Main_rp&ici=JEE_Main_article_contmap

You can also check out the B.tech Companion for college predictors, cutoffs etc:

https://www.careers360.com/btech-companion

Hope

48 Views

what is the first salary of civil engineer ? what are their work of this? what is the fee structure for this course from AMU ?

tarun kumar 16th Jan, 2020

Freshers salary depends on company to company.

Entry salary for L&T construction is 6 lakh per year.

Under Graduate Programme

Programme Name :

B.Tech. (Civil Engineering)

Number of Seats :

60

Eligibility Criteria :

Refer Guide to Admission

Jobs Prospects :

- Accredited by N.B.A. in 2016 again for 5
51 Views

I score 62marks OBC category what is percentile 7jan 1st shift

LAKSHMI AMBIKA 15th Jan, 2020

Hello Ansh,

For your score of 62 marks in jee mains paper1 you may expect your percentile between 87.34180397 - 82.68016383. this percentile is estimated based on the previous year estimates and it might vary a little.

here is the link for your reference:

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

Hope the answer is helpful.

39 Views

I had requested for APEAMCET 2020 brochure whereas Im getting the 2019 brochure. Kindly help

LAKSHMI AMBIKA 15th Jan, 2020

Hello Bragadesh Mahalingam,

it is good to know your enthusiasm towards the exam. here, please note some important dates i.e., you can start filling your online application when the application is opened by the officials at the official website sche.ap.gov (//sche.ap.gov) .in and they open the online application form on

4506 Views

if the first four moments of a distribution about the value 5 are equal to -4,22,-117 and 560. Determine (a) about the mean (b) about zero

Mounika Sonti 29th May, 2020

Hello!!!

hope you are doing great!!!!

Given moments about an arbitary origin  5.

μ1' = -4      μ 2' = 22     μ 3' = - 117        μ4'=560

Moments about mean:

μ2 = μ2' - (μ1')^2

μ1'μ2' + 2(μ1')^3

μ3=μ3' - 32

μ4 = μ4' - 4μ1'μ3' + 6μ2'(μ1)^2  - 3(μ1')^4

substituting

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