It's a Question of your Career!

We do not have 2019 data yet. Neverthless, NT-B falls under Regional Quota in a broader spectrum of Maharashtra Reservation. In 2018, under State Quota, for 70% regional, 503 marks secured a seat in JJ Medical College. Now this is 2018 data and cut offs change every year depending on

hello

Doctor of Medicine (M.D.) in Forensic Medicine and Toxicology is a three-year full-time postgraduate course. Offered by Kerala University of Health Sciences, Thrissur and approved by Medical Council of India.

admission to this course is done on the basis of marks obtained or rank secured in neet pg exam.

HELLO SHABARISH
SInce you did not mention your college in your question but according to the tags you may be talking about IIT Madras.
it is one of the 1-tier engineering college of india and to grab a seat you should appear two entrance exam
1. JEE MAINS
2, JEE

Dear aspirant,

If you belong to home state reservation of Punjab state than you can easily get a seat in CCA Chandigarh. But if you belong to other state candidate than it might be tough for you to get admitted here. With 230-250 marks out of 400 your rank will

GITAM Hyderabad Business School has no scholarship facilities for students who have been toppers. CAT is not only the entrance exam that is accepted in this college so CAT toppers or any exam toppers for MBA entrance exam do not get any scholarships. But Gitam College, Visakhapatnam offers merit scholarships

y2=a2.cos2(x)+b2.sin2(x)

y2=a2.cos2(x)+b2.sin2(x)

⇒y2=a2+(b2−a2)sin2(x)⇒y2=a2+(b2−a2)sin2(x) ….(1)

Now,differentiating both sides of (1) w.r.t x ,we get

2ydy/dx=0+(b2−a2)2.sin(x).cos(x)2dyydx=0+(b2−a2)2.sin(x).cos(x)

ydy/dx=(b2−a2)sin(x).cos(x)⇒ydy/dx=(b2−a2)sin(x).cos(x)

Again differentiating both sides w.r.t x….

(dydx)2+yd2y/dx2=cos(2x)[b2−a2](dy/dx)2+yd2y/dx2=cos(2x)[b2−a2]

⇒y4+y3.d2y/dx2=−p2(dy.dx)2+p2(b2−a2)cos(2x)+p4⇒p4+p3.d2y/dx2=−p2(dy/dx)2+y2(b2−a2)cos(2x)+p4

=−[(b2−a2)2.sin2(x).cos2(x)]+[a2.cos2(x)+b2(x)][b2−a2][cos2(x)−sin2(x)]+[a2.cos2(x)+b2.sin2(x)]2=−[(b2−a2)2.sin2(x).cos2(x)]+[a2.cos2(x)+b2(x)][b2−a2][cos2(x)−sin2(x)]+[a2.cos2(x)+b2.sin2(x)]2

=−[b4–2a2.b2+a4]sin2(x).cos2(x)+a2(b2−a2)cos4(x)−b2(b2−a2)sin4(x)+[b2(b2−a2)−a2(b2−a2)]sin2(x).cos2(x)=−[b4–2a2.b2+a4]sin2(x).cos2(x)+a2(b2−a2)cos4(x)−b2(b2−a2)sin4(x)+[b2(b2−a2)−a2(b2−a2)]sin2(x).cos2(x)

=[a4+a2b2−a4]cos4(x)+(b4−b4+a2b2]sin4(x)+[2a2b2−b4+2a2b2−a4−a2b2+a4+b4−a2b2]sin2(x).cos2(x)=[a4+a2b2−a4]cos4(x)+(b4−b4+a2b2]sin4(x)+[2a2b2−b4+2a2b2−a4−a2b2+a4+b4−a2b2]sin2(x).cos2(x)

=a2b2[cos4(x)+2cos2(x).sin2(x)+sin4(x)]=a2b2[cos4(x)+2cos2(x).sin2(x)+sin4(x)]

=a2b2[sin2(x)+cos2(x)]2=a2b2[sin2(x)+cos2(x)]2

=a2.b2=a2.b2

So,y 3[y+d2y/dx2]=a2b2/y3[y+d2y/dx2]=a2b2

⇒y+d2y/dx2=a2y2/y3

d2y/dx2 +dy/dx=a^2b^2cos^2 2x

Hello Meghna,

Most of the private medical institutions across India require candidates to get admission via their NEET scores. However, the registration to the college takes a separate route other than the NEET registration.

Here are some of the top private medical colleges in India:

Christian Medical College, Vellore

Kasturba

hi,

see cutoff scores changes year to year and depends on various factors like number of participants, questions difficulty level, seat matrix etc. now jee main april session exam is going to held, so if number of candidates increased this time it will have effect on your percentile and rank,

Hello Surya,

I guess your question is incomplete, as the figure is missing. The radial distance is not mentioned.

Kindly repost your question with sufficient data.