It's a Question of your Career!

Hello Nidhi,

CBSE board will declare 10th class compartment result on July 24, 2020, tentatively.

HOPE THIS WILL HELP YOU

GOOD LUCK!

Hello,

If you want to start your study all over again, then you can enroll yourself in NIOS, it's a valid as well as recognized board, visit the official website of NIOS at https://nios.ac.in/admission.aspx to know more details regarding this matter. Admission process is entirely online, you just have to

hello aspirant

due to the corona virus we have to be safe and sincewe all have locked down in our homes i think u can take online classes for your mba and then after all this is cured then you can proceed for your admission because MBA is a very

Hi,

There are many good universities in Tamil Nadu which offere Mechatronics course in Btech , they are:

1 SRM Institute of science and technology

2. Satyabhama Institute of technology

3. Kumaraguru Institute of Technology

and many more

For more details please visit:

https://engineering.careers360.com/colleges/list-of-mechatronics-engineering-colleges-in-tamil-nadu

Hope this helps!

Hello,

Maharaja Ranjit Singh Punjab Technical University, Bathinda  is a government university established in the year 2015 and is a state university with UGC approval. Please click the below link to know more about Maharaja Ranjit Singh Punjab Technical University, Bathinda.

https://www.careers360.com/university/maharaja-ranjit-singh-punjab-technical-university-bathinda

Hello,

You have not mentioned your query  assuming that you belong to general category your expected overall rank will be around 63437.It can be calculated by the formula (100-your total percentile)*869010/100

In January session 869010 candidates appeared in JEE Main.In 2019 the cut off for general category(home state) for admission

Hey,

dy/dx for given equation is equal to

=((e^x+e^-x)d/dx(e^x-e^-x)-(e^x-e^-x)d/dx(e^x+e^-x))/(e^x+e^-x)^2

=((e^x+e^-x)(e-(-e^-x))-(e^x-e^-x)(e^x-e^-x))/(e^x+e^-x)^2

=(((e^x+e^-x)^2)-((e^x-e^-x)^2)/(e^x+e^-x)^2

= 4/(e^x+e^-x)^2

which is the required answer.

I hope this helps.

All the best!

Chandigarh University is the best university to purse any degree according to your requirement.

• it has provision of distance learning and ca provide teaching facility and interactive sessions through online mode
• it is the university that is awarded with A+ grade by NAAC
• it has been awarded with diamond rating

Hello!

Admission to various IIITs is done on the basis of your JEE main scores. You can get into these colleges through JEE main counselling.

Thank you.

Hello,

The syllabus of JEE Mains 2020 is same as that of Class 11th and 2th.

All the chapters of NCERT Class 11th and 12th are included in JEE Mains Syllabus.

Important Topics from which questions are asked every year are -

In Physics

1. Work Power Energy
2. Rotational Motion
3. Gravitation