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Hello,
Prediction of NEET ranks highly depend upon the category of the particular candidate, the home state opening and closing ranks and also the number of students appearing for the exam. There are also other relevant factors.
Regardless, based upon the marks that you have scored you may have rank
Hello aspirant,
As per the marks that you had mentioned in ipe and eamcet, you are likely to get a rank between 41,000 to 46,000.Kindly note that this prediction is based on previous year's data and variations occur from year to year.
Here's a link for your college prediction which
Dear Aspirant
I have to say, you did a lot of hard work, the marks are a clear reminder. Although, your marks are great but the odds are stacked against you. I don't think this year's cutoffs have been released but you can use previous year's cutoff as a measuring
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Industrial Biotechnology basically works with nature to maximize and optimize existing pathways of biochemical and used for manufacturing.
Industrial Biotechnology graduates are employed in : Textiles and chemical industries, agriculture sectors, pharmaceutical firms and manufacturing industries.
According to colleges, Industrial Biotechnology engineering course is
Pharmacy college, Saifai is a public university and is university affiliated. They have total 14 faculty members and 2 acre campus area. They have facilities like hostel, library, it infrastructure, laboratories, etc on campus. Their Bachelors in pharmacy course is PCI approval and 60 intake seats. Their fees is
IPU offers B.Pharmacy as a course in only the following Colleges:
Their total seat intake is around 200-210. If your rank is 250, then you cannot get a seat here
With this rank and being non local to Telangana state, below are some of the colleges & branches you can have good chances based on the previous year data.
1. Chaitanya Bharathi Institute of Technology, Hyderabad - B. Tech in Production Engineering
2. SR Engineering college, Warangal - B.
Hello student!
Let (x - y +c1) and (x+ y +c2) be the required perpendicular lines.
The equations will be a pair of perpendicular lines if it satisfies:-
(x -y)(x + y) + c2(x - y) +c1(x + y) + c1c2 =0
The given equation can thus be written as:-
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