It's a Question of your Career!

Dear aspirant,

As you have mentioned that you want to know about your crl if your score would be 71 marks in JEE mains 2021.

See, this is a very relative thing because it would depend on the shift that you are appearing whether it's tough or easy, the type

Hello Aspirant,

See it is quite difficult to tell you an exact figure of your percentile and rank because it keeps on changing every year depending upon various factors but yes we can help you with approximate figures on the basis of analysis of previous year's data.

So If we

Dear aspirant,

As you have mentioned that you have got 50 percentile in JEE mains 2021 and you are wanting to take up computer science at any good college so let me tell you taking into consideration that you belong to general category so there is no chance for you

Hello,

Yes, a candidate who have studied Mathematics, Physics, Chemistry and Biology are eligible to pursue Computer Science in Under Graduate level. You can pursue B.Sc Computer Science, B.Tech Computer Science Engineering of BCA with Computer Science depending on your interest. The minimum Education Qualification requirement is 10+2 with Mathematics,

What rank did you get through Pearson?

Nothing is difficult if you give your maximum effort and show utmost dedication. Considering the curriculum, Computer Science Engineering is somewhat tough but it's not impossible to score 7.5, if you work hard and follow a genuine strategy then you can score more than 8 points too. However follow the

Dear aspirant,

In JEE mains and advanced, these are the type of exams in which guess work won't work at all. So, even if you are going According to the probability still there is only 25% chance of getting a correct answer and it's very less.

So, even if you

Hello,

Another approach to express a complex number is in its polar form. The rectangular coordinate form of a complex number is defined as z=a+bi.

z=r(cosθ+isinθ)

where r=|z|=sqrt(a^2+b^2)

rcosθ=a  and  rsinθ=b
Here z=2+0i

a=2    b=0

r=2    theta=0

Hence polar form is

z=2(cos0+isin0)

Hope it helped

Hey there

As I have searched everywhere there are no latest updates related to Chandigarh University reopening. However Chandigarh University has already taken decision to start colleges from August 11 2021. However the teaching for the first year students will start from September 1 and September 13 for UG and