It's a Question of your Career!

Hi,

If you have got your choice of institution within the first counselling itself & you do not wish for further upgradation, then you have to physically be available for the document verification only once while taking admission into the college. If you have applied for upgradation & you have

Hello Aspirant,

It seems that the rank that you have mentioned is CRL rank, if not then please correct me in the comment section below. Now with this CRL rank your OBC rank is expected to be around 47000-48000.

As we go through the latest cut-offs of JEE-Main 2020 of

Hello Aspirant,

Since you have not mentioned your category so considering it as General.

If we go through previous year's data of seat allotment On the basis of data mentioned in the question by you, you can go for the enlisted colleges :-

Indian Institute of Information Technology(IIIT) Kilohrad, Sonepat,

Hello Aspirant,

See it is quite difficult to tell you an exact figure of your rank because it keeps on changing every year depending upon various factors but yes we can help you with approximate figures on the basis of analysis of previous year's data.

So If we go through

Hello dear candidate,

Please provide the name of the college so that we can assist you if your question falls within our scope of expertise.

I'm not sure what you're asking.  What kind of college are you talking about? I recommend that you either leave a comment with the name

Hi Khusboo,

I believe you've missed the squares in your question. The correct question would have been ==> 9cosec²A - 9cot²A is equal to? [If you want a numeric answer]

Solution:

9cosec²A - 9cot²A

= 9(cosec²A - cot²A)

= 9 × 1 [Since cosec²A - cot²A = 1]

= 9

Dear Student,

aCosA = 1

This implies Cos A = 1/a......................................................................(Equation1)

bSinA = 1

This implies Sin A = 1/b .........................................................................(Equation 2)

Tan A  = Sin A/Cos A..............................................................................(Equation 3)

Therefore ,

From (1),(2) &  (3)

we get,

Tan A = (1/b)/(1/a)

TanA = a/b

Dear aspirant,

IIIT DHARWAD

Academic Programs

Undergraduate Programmes

B. Tech in Computer Science and Engineering (CSE) – 150 Seats

B. Tech in Data Science and Artificial Intelligence (DSAI) - 75 Seats (new program)

B.Tech in Electronics and Communication Engineering (ECE) – 75 Seats

Fee

Total fees around 1.60 lakhs

Placements