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Question : Directions: In the following question, the sentence given with a blank is to be filled in with an appropriate word. Select the correct alternative out of the four.
It is the right way___ the railway station.

Option 1: on

Option 2: of

Option 3: for

Option 4: to

Team Careers360 20th Jan, 2024

Correct Answer: to


Solution : The fourth option is the correct answer since 'to' is the preposition that indicates direction or the destination, and fits perfectly in the sentence.

The prepositions 'on', 'of' and 'for' do not go with the context of the sentence which is that the route being

51 Views

Question : Directions: Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster.
ROAR : QZNQ :: HEAR : QZDG :: DAMP : ?

Option 1: MPAD

Option 2: OLZC

Option 3: BCOA

Option 4: PMAD

Team Careers360 23rd Jan, 2024

Correct Answer: OLZC


Solution : Given:
ROAR : QZNQ :: HEAR : QZDG :: DAMP : ?

Subtract 1 from the place value of each letter of ROAR and HEAR and shuffle their position, to get the required codes –

Thus, ROAR is coded as QZNQ.

Thus, HEAR is coded

11 Views

Question : Directions: If a mirror is placed on line AB, which of the answer figures is the right image of the given figure?

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 22nd Jan, 2024

Correct Answer:


Solution : As per mirror image properties, closer things appear close to the mirror in reflection.
According to the information provided, if the mirror is placed on the left side of the figure (on line AB), the right of the reflected image will appear as the left,

10 Views

Question : If $4x–7y=3$ and $2x–y=9$, then the value of $(x–y)$ is:

Option 1: 3

Option 2: 4

Option 3: 5

Option 4: 6

Team Careers360 20th Jan, 2024

Correct Answer: 3


Solution : Given: $4x–7y=3$ and $2x–y=9$.
⇒ $4x=3+7y$ ----------(1)
⇒ $2x=9+y$ -----------(2)
Equating equation (1) and (2), we get:
⇒ $3+7y=2(9+y)$
⇒ $3+7y=18+2y$
⇒ $5y=15$
⇒ $y=3$
Putting the value of $y$ in equation (1),
⇒ $4x=3+7×3$
⇒ $4x=24$
⇒ $x=6$
So, $(x–y)=6–3$
$(x–y)=3$
Hence, the correct

4 Views

Question : Directions: In the following figure, the square represents therapists, the triangle represents geneticists, the circle represents yoga practitioners and the rectangle represents fathers. Which set of letters represents yoga practitioners who are neither geneticists nor fathers?

Option 1: C, B

Option 2: E, A

Option 3: G, C

Option 4: F, G

Team Careers360 24th Jan, 2024

Correct Answer: F, G


Solution : In the diagram, the shaded part represents the region common to yoga practitioners but, uncommon to fathers and geneticists.

Therefore, the letters that represent yoga practitioners who are neither geneticists nor fathers are F and G. Hence, the fourth option is correct.

17 Views

Question : Simplify the given expression: $\frac{4913+343}{289+49-119}$

Option 1: 24

Option 2: 26

Option 3: 22

Option 4: 20

Team Careers360 22nd Jan, 2024

Correct Answer: 24


Solution : $\frac{4913+343}{289+49-119}$
= $\frac{5256}{338-119}$
= $\frac{5256}{219}$
= 24
Hence, the correct answer is 24.

35 Views

Question : Directions: Select the option that is related to the third number in the same way as the second number is related to the first number.
91 : 104 :: 161 : ?

Option 1: 184

Option 2: 235

Option 3: 344

Option 4: 237

Team Careers360 21st Jan, 2024

Correct Answer: 184


Solution : Given:
91 : 104 :: 161 : ?

Like, 91 : 104 →91 ÷ 7 = 13; 104 ÷ 8 = 13
Similarly, for 161 : ?→161 ÷ 7 = 23; (?) ÷ 8 = 23
⇒ (?) = 23 × 8
⇒ (?) =

14 Views

Question : A man walking at 3 km/hr crosses a square field diagonally in 2 minutes. The area of the field (in square metres) is:

Option 1: 3000

Option 2: 5000

Option 3: 6000

Option 4: 2500

Team Careers360 23rd Jan, 2024

Correct Answer: 5000


Solution : A man walking at the speed of 3 km/hr = $3×\frac{5}{18}=\frac{5}{6}$ m/s
The distance covered in 2 min $ = \frac{5}{6}×2×60=100$ m
$\therefore$ Length of the diagonal = 100 m
$\therefore$ Area of the field $ = \frac{1}{2}×(\text{diagonal})^2=\frac{1}{2}×(100)^2 = 5000$ square metres
Hence, the correct

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