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Question : The Annual Session of the Congress in 1907 was held at:
Option 1: Tripuri
Option 2: Surat
Option 3: Bhopal
Option 4: Ahmedabad
Correct Answer: Surat
Solution : The correct option is Surat.
In 1907, Surat hosted the Indian National Congress's Annual Session. The internal disputes and divisions that arose within the party during the Congress' Surat Session are noteworthy. During this session of the Indian National Congress, there was a split
Question : For the triangle $PQR$, find the equation of altitude $PS$, if the co-ordinates of $P, Q, R$ are (1, 2), (2, –1), and (0, 5), respectively.
Option 1: $x–3y=–7$
Option 2: $x+3y=–5$
Option 3: $x–3y=–5$
Option 4: $x+3y=–7$
Correct Answer: $x–3y=–5$
Solution : Given: Co-ordinates of $P, Q, R$ are (1, 2), (2, –1), and (0, 5). Slope of the line $QR=\frac{y_2–y_1}{x_2–x_1}$ ⇒ $\frac{5–(–1)}{0–2}=\frac{6}{–2}=–3$ $PS$ is $\perp $ to $QR$. Let the slope of line $PS=m$ ⇒ $m×–3=–1$ ⇒ $m=\frac{1}{3}$ The equation of the line with slope $m$
Question : As of March 2022, which of the following has not been a theme of the Independence Day celebrations?
Option 1: Nation First Always First
Option 2: Yaad Karo Kurbani
Option 3: Service Before Self
Option 4: Towards True Freedom
Correct Answer: Service Before Self
Solution : The correct answer is Service Before Self.
'Seva Paramo Dharma' means service before self, which is the motto of the Indian Army. The Indian Army is a major constituent of national power. It is the biggest voluntary military force in the world.
Question : Directions: Which of the following four options will replace the question mark (?) in the following series? 9, 45, ?, 540, 1080
Option 1: 180
Option 2: 240
Option 3: 300
Option 4: 360
Correct Answer: 180
Solution : Given: 9, 45, ?, 540, 1080
Multiply the numbers starting from 5 in decreasing order – 9 × 5 = 45; 45 × 4 = 180; 180 × 3 = 540; 540 × 2 = 1080
So, the missing number is 180. Hence, the first
Question : Manoj bought two TVs for Rs. 2280. He sold one at a loss of 20% and the other at a profit of 10%. If each TV was sold for the same price, then what is the cost price of the TV that was sold at a loss?
Option 1: Rs. 1380
Option 2: Rs. 1320
Option 3: Rs. 1050
Option 4: Rs. 1440
Correct Answer: Rs. 1320
Solution : Let the cost price of the TV sold at a loss as L and the cost price of the TV sold at a profit as P. Given that Manoj bought two TVs for Rs. 2280. $⇒L + P = 2280$ ____(1) He sold the
Question : Find the three consecutive numbers such that twice the first, three times the second and four times the third together make 191.
Option 1: 19, 20 and 21
Option 2: 21, 22 and 23
Option 3: 20, 21 and 22
Option 4: 21, 23 and 24
Correct Answer: 20, 21 and 22
Solution : Let the three consecutive numbers be $x, x+1$ and $x+2$. $⇒ 2x + 3(x+1) + 4(x+2) = 191$ $⇒ 2x + 3x + 3 + 4x + 8 = 191$ $⇒ 9x + 11 = 191$ $⇒ 9x = 180$ $⇒ x
Question : What is the value of $\frac{\frac{1}{3}+\frac{1}{3}\times\frac{1}{3}}{\frac{1}{3}\times\frac{1}{3}+\frac{1}{3}}$?
Option 1: 1
Option 2: 3
Option 3: $\frac{1}{3}$
Option 4: $\frac{1}{2}$
Correct Answer: 1
Solution : Given: $\frac{\frac{1}{3}+\frac{1}{3}\times\frac{1}{3}}{\frac{1}{3}\times\frac{1}{3}+\frac{1}{3}}$ $= \frac{\frac{1}{3}+\frac{1}{9}}{\frac{1}{9}+\frac{1}{3}}$ $= \frac{\frac{4}{9}}{\frac{4}{9}}$ $= 1$ Hence, the correct answer is 1.
Question : Name the clan Buddha belonged to
Option 1: Gnathrika
Option 2: Maurya
Option 3: Shakya
Option 4: Kuru
Correct Answer: Shakya
Solution : The correct option is Shakya.
Buddha was born to Shakya clan royal parents in Lumbini, in what is now Nepal. In his early years, he was called Siddhartha Gautama. His mother was Queen Maya, and his father was King Suddhodana, the Shakya clan's ruler.
Question : Direction: In the given question, select the related letter from the given alternatives.
BED : GJI :: LON : ?
Option 1: QTS
Option 2: PTS
Option 3: QST
Option 4: KNH
Correct Answer: QTS
Solution : Given:
In the first pair →
B + 5 = G; E + 5 = J; D + 5 = I
Similarly, in the second pair →
L + 5 = Q; O + 5 = T; N
Question : Determine the value of $x$, if $x = \frac{(943+864)^2-(943-864)^2}{(1886\times1728)}$.
Option 2: 4
Option 3: 79
Option 4: 1789
Solution : Given: $x = \frac{(943+864)^2-(943-864)^2}{(1886\times1728)}$ This can be simplified using the identity $(a+b)^2 - (a-b)^2 = 4ab$, where $a = 943$ and $b = 864$. ⇒ $x = \frac{4×943×864}{1886\times1728}$ ⇒ $x = \frac{2×943×2×864}{1886\times1728}$ ⇒ $x=1$ Hence, the correct answer is $1$.
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