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22 Views

Question : Which Chola ruler built the Brihadeshwara Temple at Tanjore?

Option 1: Rajaraja I

Option 2: Rajendra I

Option 3: Vijayalaya

Option 4: Rajendra III

Team Careers360 25th Jan, 2024

Correct Answer: Rajaraja I


Solution : The correct answer is Rajaraja I.

Rajaraja I, the king of the Chola Dynasty, constructed the Brihadeshwara Temple in the southeast of the capital city of Thanjavur in 1010, in the Kaveri (Cauvery) basin (r. 985–1014). In addition, the king's name, Rajarajeshwara Temple,

16 Views

Question : The acid which is secreted by the glands in the stomach wall is

Option 1: Sulphuric acid

Option 2: Hydrochloric acid

Option 3: nitric acid

Option 4: Phosphoric acid

Team Careers360 23rd Jan, 2024

Correct Answer: Hydrochloric acid


Solution : The correct answer is hydrochloric acid.

Hydrochloric acid is released in stomach and it has a pH between 1.5 to 3.5. It is the main component of gastric juice and is released by parietal cells of  gastric mucosa in the fundus and corpus. This

9 Views

Question : PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that $\angle {APB}=100^{\circ}$, then $\angle {OAB}$ is equal to:

Option 1: $45^{\circ}$

Option 2: $35^{\circ}$

Option 3: $70^{\circ}$

Option 4: $50^{\circ}$

Team Careers360 25th Jan, 2024

Correct Answer: $50^{\circ}$


Solution :
According to the question,
$\angle$APB = 100º
Also, $\angle$ OAP = $\angle$ OBP = 90º (the angle between the tangent and radius at the point of contact is 90º)
Since the sum of all angles of a quadrilateral is 360º.
$\angle$ OAP + $\angle$ OBP

16 Views

Question : Directions: Words given on the left side of (::) are related to each other by some Logic/Rule/Relation. Select the missing word/word pair on the right side of (::) from the given alternatives based on the same Logic/Rule/Relation.
Ottawa : Canada :: ?

Option 1: Nairobi : Kenya

Option 2: Russia : Moscow

Option 3: Greece : Athens

Option 4: Spain : Madrid

Team Careers360 23rd Jan, 2024

Correct Answer: Nairobi : Kenya


Solution : Given:
Ottawa : Canada :: ? (Ottawa is the capital city of Canada.)

Let's check the given options –
First option: Nairobi : Kenya; Nairobi is the capital city of Kenya.
Second option: Russia : Moscow; Moscow is the capital city of Russia,

17 Views

Question : Directions: Words given on the left side of (::) are related to each other by some Logic/Rule/Relation. Select the missing word/word pair on the right side of (::) from the given alternatives based on the same Logic/Rule/Relation.
Ottawa : Canada :: ?

Option 1: Nairobi : Kenya

Option 2: Russia : Moscow

Option 3: Greece : Athens

Option 4: Spain : Madrid

Team Careers360 23rd Jan, 2024

Correct Answer: Nairobi : Kenya


Solution : Given:
Ottawa : Canada :: ? (Ottawa is the capital city of Canada.)

Let's check the given options –
First option: Nairobi : Kenya; Nairobi is the capital city of Kenya.
Second option: Russia : Moscow; Moscow is the capital city of Russia,

18 Views

Question : Who was awarded the Nobel Prize in Literature 2019 "for an influential work that with linguistic ingenuity has explored the periphery and the specificity of human experience"?

Option 1: Didier Queloz

Option 2: Olga Tokarczuk

Option 3: Jim Peebles

Option 4: Peter Handke

Team Careers360 24th Jan, 2024

Correct Answer: Peter Handke


Solution : The correct answer is Peter Handke.

The Nobel Prize in Literature 2019 was awarded to Austrian author Peter Handke. Recognised for his influential work, characterised by linguistic ingenuity, Handke has extensively explored the periphery and specificity of human experience. His notable literary

14 Views

Question : If $b \sin \theta=a$, then $\sec \theta+\tan \theta=?$

Option 1: $\sqrt{\frac{b+a}{b-a}}$

Option 2: $\sqrt{\frac{1}{b+a}}$

Option 3: $\sqrt{\frac{1}{b-a}}$

Option 4: $\sqrt{\frac{b-a}{b+a}}$

Team Careers360 24th Jan, 2024

Correct Answer: $\sqrt{\frac{b+a}{b-a}}$


Solution : $b \sin \theta = a$
$\sin\theta = \frac{a}{b}$
So, Perpendicular = $a$ & Hypotenuse = $b$
$(Hypotenuse)^2= (Perpendicular)^2+ (Base)^2$
⇒ $b^2= a^2 + (Base)^2$
⇒ $(Base)^2 = b^2- a^2$
⇒ $(Base) = \sqrt{b^2- a^2}$
$\sec \theta = \frac{(Hypotenuse)}{(Base)}= \frac{b}{\sqrt{b^2- a^2}}$
$\tan \theta= \frac{(Perpendicular)}{(Base)}= \frac{a}{\sqrt{b^2- a^2}}$

18 Views

Question : Who was the founder of the Theosophical Society?

Option 1: Justice Ranade

Option 2: Madame Blavatsky

Option 3: Annie Besant

Option 4: Bal Gangadhar Tilak

Team Careers360 25th Jan, 2024

Correct Answer: Madame Blavatsky


Solution : The correct answer is Madame Blavatsky.

A spiritual and mystic group is the Theosophical Society. Only in 1879 did this philosophy begin to take root in Indian culture. The society's main office was established in 1882 in Adyar, an Indian city close to Madras

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