Question : A can finish a task in 60 days. He works at it for 15 days and then, B alone finishes the remaining work in 48 days. In how much time can A and B, working together, finish the task?
Option 1: $\frac{960}{31}\ \text{days}$
Option 2: $\frac{171}{37}\ \text{days}$
Option 3: $51\ \text{days}$
Option 4: $45\ \text{days}$
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Correct Answer: $\frac{960}{31}\ \text{days}$
Solution :
A finishes a task in 60 days.
A works at it for 15 days.
In 15 days, A completes $\frac{15}{60} = \frac{1}{4}$th of the task
Work remaining = 1 – $\frac{1}{4} = \frac{3}{4}$th of the task
B completes the remaining $\frac{3}{4}$th of the task in 48 days.
$\therefore$ B can complete the entire task in $\frac{48\times 4}{3} = 64$ days
A and B together can complete in 1 day $=\frac{1}{60} + \frac{1}{64} = \frac{31}{960}$th of the task.
$\therefore$ A and B together can complete the task in $\frac{960}{31}$ days.
Hence, the correct answer is $\frac{960}{31}$ days.
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