A girl leaves her home every day at 10:00 am and reaches office at 11 am. one day she leaves home at normal time and travelled the first half of the distance at the 2/3 of her original speed, at what speed should she travel at the 2nd half so that she reaches office on time.
Answer (1)
Hi
She'll at 9.25 am. She'll take 85 minutes
Step-by-step explanation:
regular speed is x/ninety kms consistent with minute.
1/three of the gap is travelled in three/four of the speed. therefore time taken is 40 mts. 2/3 is travelled
in 45 mts. therefore 85 mts.
Hope it helps
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