a lamp is working on ac volteg of 250 volts,takes a current of 0.8 amp. its radiates a flux of 3000 lumens calculate its luminous efficiency. find MSCP and Express it per watt
Hello candidate,
The power produced by lighting a lamp on an AC voltage of 250 volts, and taking a current of 0.8 ampere for working.
The formula for power is equal to voltage multiplied by current, show the power produced will be equal to 200 Watt. So, efficiency of the lamp will be equal to 200/3000= 0.06.
Hope that this answer was helpful for you.
Have a Good day!!