expand: (2x-y+2)3 please solve
Answer (1)
8th Jun, 2021
Dear aspirant,
You can solve this pretty normally by binomial expansion , so the value of n here is 3 so go by the formula:-
Take 2x as 1st and 2-y as second group
nC0 (2x)^3 (2-y)^0+ nC1(2x)^2 (2-y)^1+ nC2 (2x)^1(2-y)^2 + nC3 (2x)^0 (2-y)^3.
Just evaluate this equation ,you will get your desired result.
Comments (0)
Related Questions
solve (2x+4y-6)dy=(2x-5y +3)dx
1852 Views
