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expand: (2x-y+2)3 please solve

KRISHNA SHEKHAR 8th Jun, 2021

Answer (1)

ayanmukherjee045 8th Jun, 2021

Dear aspirant,

You can solve this pretty normally by binomial expansion , so the value of n here is 3 so go by the formula:-

Take 2x as 1st and 2-y as second group

nC0 (2x)^3 (2-y)^0+ nC1(2x)^2 (2-y)^1+ nC2 (2x)^1(2-y)^2 + nC3 (2x)^0 (2-y)^3.

Just evaluate this equation ,you will get your desired result.

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