for 98,6369 percentile what could be rank and which best NIT admission i may get

Hello Aspirant,

The exact prediction would be difficult about the exact rank & admission possibilities. You may calculate your expected rank by this formula

100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Using the formula

(100 - your total score) X 869010 /100

Your probable rank will be 11,845.

As per the previous year cutoff, You can get

National Institute of Technology Karnataka Surathkal, National Institute of Technology Warangal, Motilal Nehru National Institute of Technology Allahabad Prayagraj, National Institute of Technology Rourkela, Malaviya National Institute of Technology Jaipur- Civil & Chemical Engineering Etc.

To know your other admission possibilities & branches, You can use JEE Main College Predictor tool.

JEE Main College Predictor 2020 - Predict Colleges based on your JEE Main Rank

JEE Main College Predictor – Know your College Admission Chances Based on your Rank/Percentile, Home State, Caste, Gender, Exam Result & Get ...

Good Luck!