Question : How many tiles, each 4 decimetre square, will be required to cover the floor of a room 8 m long and 6 m broad?
Option 1: 200
Option 2: 260
Option 3: 280
Option 4: 300
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Correct Answer: 300
Solution :
We have to find how many tiles, each 4 decimetre square, will be required to cover the floor of a room 8 m long and 6 m broad.
Here, the area of the floor = (8 × 6) = 48 m
2
Now 48 m
2
= (48 × 100) = 4800 dm
2
Also, the area of a square tile = (4 × 4) = 16 dm
2
Therefore, the required number of tiles = $\frac{4800}{16}=300$
Hence, the correct answer is 300.
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