I got 69213 in crl rank which nit will prefer to me for CSE
Hello student ,
As you have not mentioned your category so it would be tough to say anything but still assuming your general category you have less chances to get with this crl rank because as ypu know cut off used to change every year due to various factors
So i will suggest you to use the link below and check your chances in another colleges .
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Hope this information will help you !
Hello Student,
A rank of 69213 in CRL is a bit low of a rank. Due to the competition increasing by the minute everyday, the need for scoring higher marks and scores keep increasing more and more. Hence, unfortunately the top nits and IITs would be tough to get into with this score. Also other Centrally Funded Technical Institutes ( CFTIs) such as the IIITs also would be a bit tough. There might be some chances of you getting into newer NITs such as NIT Andhra Pradesh or NIT Pondicherry into courses that are relatively lesser in demand such as metallurgy.
However, since you have not mentioned any reservations or quotas, the chances of you getting into some very well reputed universities are a bit on the higher side if you have any reservation. Computer Science Engineering is a course that is very much in demand and much sought after course and the chances are very low. Since you have mentioned the courses such as CSE or IT, there are some other universities into which you have a good chance of getting into. However, these are courses that are very high in demand. Hence I would suggest you to apply for other universities
Some other good universities with this rank would be:
1. SSN College of Engineering, Chennai
2. SASTRA Deemed to be University, Thanjavur
3. Andhra University, Andhra Pradesh
4. Delhi University
5. Shiv Nadar University
6. VIT, Vellore
7. Manipal Institute of Technology
You can check your colleges using the link below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer



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