I GOT 90%/ IN JEE MAIN PAPER 1 2020.WHAT IS RANK?

Dear Aspirant,

The formula to convert percentage into rank in Jee main is:

(100-NTA percentile score)*869010/100

Where,

869010- total number of candidates that appeared for JEE

So your expected rank approximately is 86901.

Thank you!!

Hello,
With your 90 Percentile in JEE mains 2020, your rank would be around 85000 to 95000.
Withthis rank you won't be able to get any seat in any NITs, IIITs and GFTIs. Even your category reservation won't be of any help here.
I would request you to go for some top private engineering colleges in India which accept JEE mains score and also conduct their own entrance exams which are very easy compared to JEE mains. Some of the colleges are

• SRM University, Chennai
• Amity University Noida
• Manipal University Manipal
• Sharda University, Greater Noida

Here's the link for that list https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/colleges/ranking/top-private-engineering-colleges-in-India-accepting-jee-main-score&ved=2ahUKEwiqlf2N2b_qAhWb7XMBHbCcBQYQFjAEegQIAhAJ&usg=AOvVaw3gEfP5DuTaBP3lMOFChRgI

Hope it helps