I got 95.2 percentile in jee 2020 January attempt. Can u plz calculate my obc ncl rank? Which college can i get with this rank?
Answer (1)
Student Expert
24th Feb, 2020
Hello student you can easily calculate and get your rank by using this formula
100-(your total percentile) 869010 /100
In your case your rank must be around 41712.
With this rank being an OBC Candidate its difficult to get admission in good Nit/iiit as we all know that seats are very limited and admission is directly based on all india rank.
You can easily predict your college by using our college predictor its very user friendly and very helpful.
https://engineering.careers360.com/jee-main-college-predictor
In case if total number of applicants increases then your rank must decrease, if you want to appear in jee main April exam you need to apply for it. Application form begins from 07th of February and shall remain open till 07th of March 2020.
For more updates on jee main refer the link mentioned below.
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main/amp
Feel free to comment if you have any doubt
Good luck
100-(your total percentile) 869010 /100
In your case your rank must be around 41712.
With this rank being an OBC Candidate its difficult to get admission in good Nit/iiit as we all know that seats are very limited and admission is directly based on all india rank.
You can easily predict your college by using our college predictor its very user friendly and very helpful.
https://engineering.careers360.com/jee-main-college-predictor
In case if total number of applicants increases then your rank must decrease, if you want to appear in jee main April exam you need to apply for it. Application form begins from 07th of February and shall remain open till 07th of March 2020.
For more updates on jee main refer the link mentioned below.
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main/amp
Feel free to comment if you have any doubt
Good luck
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